bash 如何在awk脚本中将一列转换为日期格式？
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How to convert one column to date format in awk script?
提问by user710818
cat test.txt |
awk 'BEGIN { FS = "\t" } ;{ print =strftime("%d %b %Y",) "\t" }'
I have received:
我收到了：
31 12 1969 2012-09-27
But I have expected:
但我已经预料到：
27 Sep 2012 2012-09-27
Where is the error? Thanks.
错误在哪里？谢谢。
回答by Kent
if you really want to convert the format with awk build-in functions, this example may help you:
如果你真的想用 awk 内置函数转换格式，这个例子可以帮助你：
kent$ echo "2012-09-27" |awk '{t= mktime(datespec)
strftime([format [, timestamp[, utc-flag]]])
;gsub("-"," ",t);print strftime("%d %b %Y", mktime(t" 00 00 00"))}'
27 Sep 2012
read the description of following functions in man page:
阅读手册页中对以下功能的描述：
awk 'BEGIN {FS=OFS="\t"}{t=;gsub("-"," ",t); print strftime("%d %b %Y", mktime(t" 00 00 00")),}' test.txt
edittry to fix you old command, but no input file, cannot test it...
编辑尝试修复您的旧命令，但没有输入文件，无法对其进行测试...
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