xcode '...' 不是后缀一元运算符 - Swift 3
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时间：2020-09-15 10:10:52 来源:igfitidea点击:
'...' is not a postfix unary operator - Swift 3
提问by Nikola Lukic
I just want to remove one part of string .
我只想删除 string 的一部分。
if let dotRange = detailArticleContent?.range(of: "<iframe") {
detailArticleContent.removeSubrange( dotRange.lowerBound... < detailArticleContent.endIndex )
//In this line i got err : '...' is not a postfix unary operator
}
回答by Tj3n
Use either ...(close range) or ..<(half close range, before last), there's nothing like ... <
使用...(close range) 或..<(half close range, before last)，没有什么比... <
回答by iOS
In my case i given space between 0..<and dictionary.count
在我的情况下，我在0..<和dictionary.count之间给出了空间
Correct one is :
正确的一个是：
0..<dictionary.count
//Wrong
let dictionary = dic["predictions"] as! [String:Any]
print(dictionary)
for index in 0..< dictionary.count {
print(<#T##items: Any...##Any#>)
}
//Correct
let dictionary = dic["predictions"] as! [String:Any]
print(dictionary)
for index in 0..<dictionary.count {
print(<#T##items: Any...##Any#>)
}
