xcode 无法从 Alamofire 3.3.0 获取服务器错误消息
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Could not get the server error message from Alamofire 3.3.0
提问by Joseph Wahba
It is my first time for me to use Alamofire, and it got me really frustrated.
这是我第一次使用Alamofire，这让我非常沮丧。
I'm using the following code to call a signup API on the backend API
我正在使用以下代码在后端 API 上调用注册 API
Alamofire.request(.POST, "\(self.authBaseURL)/signup", parameters: params, headers: headers, encoding: .JSON)
.validate(statusCode: 200..<300)
.validate(contentType: ["application/json"])
.responseJSON { response in
switch response.result {
case .Success(let JSON):
print("Success with JSON: \(JSON)")
success(updatedUser)
case .Failure(let error):
print("Request failed with error: \(error)")
failure(error)
}
}
The problem is that the error object I'm getting in the .Failurefunction doesn't contain the server side message.
I have tried to access the rest of the objects (request, response, data, result) I could not find my error message anywhere
问题是我在.Failure函数中得到的错误对象不包含服务器端消息。我试图访问其余的对象（请求、响应、数据、结果）我在任何地方都找不到我的错误消息
I'm always getting the following error, no matter what the server message has to say. Request failed with error:
无论服务器消息怎么说，我总是收到以下错误。请求失败，错误：
FAILURE: Error Domain=com.alamofire.error Code=-6003 "Response status code was unacceptable: 400" UserInfo={NSLocalizedFailureReason=Response status code was unacceptable: 400}
失败：错误域=com.alamofire.error 代码=-6003“响应状态代码不可接受：400” UserInfo={NSLocalizedFailureReason=响应状态代码不可接受：400}
Is there is anything wrong I'm doing?
我做错了什么吗？
Swift 2.2, AlamoFire 3.3.0, Xcode 7.3
Swift 2.2、AlamoFire 3.3.0、Xcode 7.3
回答by Joseph Wahba
I managed to get it to work exactly the way I want is by dropping the status validation and check for the statusCode manually
我设法让它完全按照我想要的方式工作，方法是删除状态验证并手动检查 statusCode
Alamofire.request(.POST, "\(self.authBaseURL)/signup", parameters: params, headers: headers, encoding: .JSON)
.validate(contentType: ["application/json"])
.responseJSON { response in
if response.response?.statusCode == 200 {
print("Success with JSON: \(response.result.value)")
success(updatedUser)
}
else {
let error = response.result.value as! NSDictionary
let errorMessage = error.objectForKey("message") as! String
print(errorMessage)
failure(errorMessage)
}
}
回答by Kiran jadhav
updated for swift 3 :
为 swift 3 更新：
Used below lines of code:-
使用以下代码行：-
Alamofire.request(escapedString!, method: .get, encoding: JSONEncoding.default)
.validate(contentType: ["application/json"])
.responseJSON { response in
if response.response?.statusCode == 200 {
print("Success with JSON: \(String(describing: response.result.value))")
}
else {
let error = (response.result.value as? [[String : AnyObject]])
print(error as Any)
}
}
回答by SafeFastExpressive
This is how to get the error domain, code and user info with Alamofire 4 and Swift 3. User info contains the error strings.
这是使用 Alamofire 4 和 Swift 3 获取错误域、代码和用户信息的方法。用户信息包含错误字符串。
Alamofire.request(.POST, "\(self.authBaseURL)/signup", parameters: params, headers: headers, encoding: .JSON)
.validate(statusCode: 200..<300)
.validate(contentType: ["application/json"])
.responseJSON { response in
switch response.result {
case .Success(let JSON):
print("Success with JSON: \(JSON)")
success(updatedUser)
case .Failure(let error):
let errorCode = error._code
let errorDomain = error._domain
let userInfo = error._userInfo
print("Request failed with error: \(error), code: \(errorCode), domain: \(errorDomain)")
failure(error)
}
}
