java 有没有一种方便的方法可以将逗号分隔的字符串转换为哈希图
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Is there a convenient way to convert comma separated string to hashmap
提问by secondflying
String format is (not json format)：
字符串格式为（非json格式）：
a="0PN5J17HBGZHT7JJ3X82", b="frJIUN8DYpKDtOLCwo/yzg="
I want convert this string to a HashMap:
我想将此字符串转换为 HashMap：
key awith value 0PN5J17HBGZHT7JJ3X82
键a与值0PN5J17HBGZHT7JJ3X82
key bwith value frJIUN8DYpKDtOLCwo/yzg=
键b与值frJIUN8DYpKDtOLCwo/yzg=
Is there a convenient way? Thanks
有没有方便的方法？谢谢
What I've tried:
我试过的：
Map<String, String> map = new HashMap<String, String>();
String s = "a=\"00PN5J17HBGZHT7JJ3X82\",b=\"frJIUN8DYpKDtOLCwo/yzg=\"";
String []tmp = StringUtils.split(s,',');
for (String v : tmp) {
String[] t = StringUtils.split(v,'=');
map.put(t[0], t[1]);
}
I get this result:
我得到这个结果：
key awith value "0PN5J17HBGZHT7JJ3X82"
键a与值"0PN5J17HBGZHT7JJ3X82"
key bwith value "frJIUN8DYpKDtOLCwo/yzg
键b与值"frJIUN8DYpKDtOLCwo/yzg
for key a, the start and end double quotation marks(") is unwanted; for key b, the start double quotation marks(") is unwanted and the last equals sign(=) is missing.
Sorry for my poor english.
对于 key a，开始和结束双引号 (") 是不需要的；对于 key b，开始双引号 (") 是不需要的，并且缺少最后一个等号 (=)。对不起，我的英语不好。
回答by Ryan Stewart
Probably you don't care that it's a HashMap, just a Map, so this will do it, since Properties implements Map:
可能你不在乎它是一个 HashMap，只是一个 Map，所以这会做到，因为 Properties 实现了 Map：
import java.io.StringReader;
import java.util.*;
public class Strings {
public static void main(String[] args) throws Exception {
String input = "a=\"0PN5J17HBGZHT7JJ3X82\", b=\"frJIUN8DYpKDtOLCwo/yzg=\"";
String propertiesFormat = input.replaceAll(",", "\n");
Properties properties = new Properties();
properties.load(new StringReader(propertiesFormat));
System.out.println(properties);
}
}
Output:
输出：
{b="frJIUN8DYpKDtOLCwo/yzg=", a="0PN5J17HBGZHT7JJ3X82"}
If you absolutely need a HashMap, you can construct one with the Properties object as input: new HashMap(properties).
如果你绝对需要一个HashMap，你可以构造一个与属性对象作为输入：new HashMap(properties)。
回答by Kumar Vivek Mitra
Split the String on the Basis of commas (",")and then with with ("=")
在基础上拆分字符串commas (",")，然后使用("=")
String s = "Comma Separated String";
HashMap<String, String> map = new HashMap<String, String>();
String[] arr = s.split(",");
String[] arStr = arr.split("=");
map.put(arr[0], arr[1]);
回答by vels4j
Added few changes in Ryan's code
在 Ryan 的代码中添加了一些更改
public static void main(String[] args) throws Exception {
String input = "a=\"0PN5J17HBGZHT7JJ3X82\", b=\"frJIUN8DYpKDtOLCwo/yzg=\"";
input=input.replaceAll("\"", "");
String propertiesFormat = input.replaceAll(",", "\n");
Properties properties = new Properties();
properties.load(new StringReader(propertiesFormat));
Set<Entry<Object, Object>> entrySet = properties.entrySet();
HashMap<String,String > map = new HashMap<String, String>();
for (Iterator<Entry<Object, Object>> it = entrySet.iterator(); it.hasNext();) {
Entry<Object,Object> entry = it.next();
map.put((String)entry.getKey(), (String)entry.getValue());
}
System.out.println(map);
}
回答by Sandeep
You can also use the regex as below.
您还可以使用如下正则表达式。
Map<String,String> data = new HashMap<String,String>();
Pattern p = Pattern.compile("[\{\}\=\, ]++");
String[] split = p.split(text);
for ( int i=0; i+2 <= split.length; i+=2 ){
data.put( split[i], split[i+1] );
}
return data;
