javascript JSON 中的正则表达式模式？
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Regex pattern in JSON?
提问by Eric
I'm trying to have a single JSON file to validate data both in front (JS) and back (PHP). I cannot figure out how to have my pattern in a json string, PHP won't convert it. Here's what I'd like to use (email validation):
我正在尝试使用一个 JSON 文件来验证前端 (JS) 和后端 (PHP) 的数据。我不知道如何在 json 字符串中包含我的模式，PHP 不会转换它。这是我想使用的（电子邮件验证）：
'{"name":"email", "pattern":"^[a-z0-9]+(\.[_a-z0-9]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,15})$"}'
I suppose there's something in pattern that doesn't get treated as a string? This as it is, won't convert to an object in PHP. I shouldn't have to escape anything but I might be wrong...
我想模式中的某些东西不会被视为字符串？这实际上不会转换为 PHP 中的对象。我不应该逃避任何事情，但我可能错了......
thanks
谢谢
Edit: Tried this as suggested in comments:
编辑：按照评论中的建议尝试此操作：
json_decode('{"name":"email", "pattern":"^[a-z0-9]+(\.[_a-z0-9]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,15})$"}??'); ==> NULL
回答by ljacqu
The problem are the backslashes \. Use two to signal that there is one and it will work well:
问题是反斜杠\。使用两个来表示有一个，它会运行良好：
{"name":"email","pattern":"^[a-z0-9]+(\.[_a-z0-9]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,15})$"}
The above is valid JSON but will cause trouble as PHP string, because \\will already be interpreted as one \before it is passed to json_decode(), and we're back where we started from. As decezekindly pointed out in the comments, this can be solved by adding four backslashes:
以上是有效的 JSON，但作为 PHP 字符串会引起麻烦，因为在传递给 之前\\已经被解释为一个，我们又回到了我们开始的地方。正如deceze在评论中友好指出的那样，这可以通过添加四个反斜杠来解决：\json_decode()
{"name":"email","pattern":"^[a-z0-9]+(\\.[_a-z0-9]+)*@[a-z0-9-]+(\\.[a-z0-9-]+)*(\\.[a-z]{2,15})$"}
Or by immediately passing the contents from file_get_contents()(or similar) to json_decode().
或者立即将内容从file_get_contents()（或类似的）传递到json_decode().
