Java 将字符串转换为十进制（ ASCII ）？
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Java Conversion of String to decimal ( ASCII )?
提问by reinhard.lee
String buffer = "c";
Conversion by Decimal. I wanna change buffer value to decimal value.
按十进制转换。我想将缓冲区值更改为十进制值。
In ASCII Table
DEC HEX CHAR
99 63 c
So, Finally
buffer -> 99 ( return value int or String and something )
所以，最后
buffer -> 99 ( return value int or String and something )
How Can I Change that value?
如何更改该值？
Integer.parseInt(buffer, 12) -> returns 12
But I wanna get 99
但我想得到 99
is it Possible to conversion?
可以转换吗？
采纳答案by Ankur
String buffer = "c";
char ch = buffer.charAt(0);
System.out.println((int)ch);
This should do it.
这应该这样做。
回答by Scary Wombat
try
尝试
System.out.println((int)ch);
where ch is a char
其中 ch 是一个字符
Of course in you code you have a string, so maybe you need to get the first char or something
当然在你的代码中你有一个字符串，所以也许你需要得到第一个字符或其他东西
回答by Sandesh Vaze
String buffer = "abc";
for(int i=0;i<buffer.length();i++)
{
System.out.println((int)buffer.charAt(i));
}
