java 使用 JPA 保存到数据库中的键“PRIMARY”的重复条目

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时间:2020-10-31 20:23:26  来源:igfitidea点击:

Duplicate entry for key 'PRIMARY' using JPA to persist into database

javamysqlhibernatejpa

提问by user1694873

I have an error with JPA persisting into my database, the error occurs when i persist a second file into the DB. I have a requirement to import numerous datasets, with 5 sheets each. There is a requirement to update each table even if some of the same data is already in there. At the moment i get the following error

JPA 持久化到我的数据库时出现错误,当我将第二个文件持久化到数据库中时发生错误。我需要导入大量数据集,每个数据集有 5 张。即使某些相同的数据已经存在,也需要更新每个表。目前我收到以下错误

Error

错误

17:26:35,315 WARN  [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (http-localhost-127.0.0.1-8080-1) SQL Error: 1062, SQLState: 23000
17:26:35,316 ERROR [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (http-localhost-127.0.0.1-8080-1) Duplicate entry '0' for key 'PRIMARY'

Database Script

数据库脚本

My script to create the DB is as follows:

我创建数据库的脚本如下:

CREATE DATABASE IF NOT EXISTS sampleDB;



use sampleDB;



CREATE TABLE IF NOT EXISTS `Table1`(`mcc` int(10) NOT NULL,`mnc` int(10) NOT NULL,`operator` varchar(50) DEFAULT NULL,`country` varchar(50) DEFAULT NULL,

    PRIMARY KEY (`mcc`,`mnc`))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table2`(`tac` int(10) NOT NULL,`marketingName` varchar(50) DEFAULT NULL,`manufacturer` varchar(50) DEFAULT NULL,

    `accessCapability` varchar(200) DEFAULT NULL,`model` varchar(50) DEFAULT NULL,`vendorName` varchar(50) DEFAULT NULL,

    `ueType` varchar(20) DEFAULT NULL,`os` varchar(20) DEFAULT NULL,`inputMode` varchar(20) DEFAULT NULL,PRIMARY KEY (`tac`))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table3`(`causeClass` varchar(10) NOT NULL,`description` varchar(255) NOT NULL,PRIMARY KEY (`causeClass`))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table4`(`causeCode` int(5) NOT NULL,`eventId` int(5) NOT NULL,`description` varchar(255) DEFAULT NULL,

    PRIMARY KEY (`causeCode`,`eventId`) ON UPDATE NO ACTION))ENGINE=InnoDB;



CREATE TABLE IF NOT EXISTS `Table5`(`baseDataTableId` int(11) NOT NULL AUTO_INCREMENT,`dateTime` DATETIME NOT NULL,`eventId` int(5) NOT NULL,`causeClass` varchar(10) NOT NULL,

  `ueType` int(15) NOT NULL,`market` int(10) NOT NULL,`operator` int(10) NOT NULL,`cellId` tinyint(2) DEFAULT NULL,`duration` smallint(7) DEFAULT NULL,

  `causeCode` int(5) NOT NULL,`neVersion` varchar(7) DEFAULT NULL,`imsi` varchar(255) DEFAULT NULL,`hier3Id` varchar(255) DEFAULT NULL,`hier32Id` varchar(255) DEFAULT NULL,

  `hier321Id` varchar(255) DEFAULT NULL,PRIMARY KEY (`baseDataTableId`))ENGINE=InnoDB;

Java Hibernate properties

Java 休眠属性

My Hibernate properties are as follows:

我的 Hibernate 属性如下:

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
   xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="
        http://java.sun.com/xml/ns/persistence
        http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
   <persistence-unit name="primary">
      <jta-data-source>java:jboss/datasources/MySqlDS</jta-data-source>
      <properties>
         <!-- Properties for Hibernate -->
         <property name="hibernate.hbm2ddl.auto" value="update" />
         <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
         <property name="hibernate.show_sql" value="false" />
         <property name="hibernate.format_sql" value="false" />
      </properties>
   </persistence-unit>
</persistence>

Java

爪哇

Entity Class example:

实体类示例:

@Entity
@Table(name = "Table3")
public class Table3 {

        @Id
        private int causeClass;
        private String description;

        public Table3(){}

        public Table3(int causeClass, String description) {
            super();
            this.causeClass = causeClass;
            this.description = description;
        }

        // getters & setters

}

Any ideas how to solve this problem?

任何想法如何解决这个问题?

回答by Berto

Be sure you are using the good EntityManager's method to update existing entities. It seems that your trying to do a persist operation instead of a merge for existing entities. When persisting antity, try to catch EntityExistsException or PersistenceException and in the catch block, call merge method. For example :

请确保您正在使用良好的 EntityManager 方法来更新现有实体。您似乎试图对现有实体执行持久操作而不是合并。持久化antity时,尝试捕获EntityExistsException或PersistenceException,并在catch块中调用merge方法。例如 :

save(Enity item){
    try{
        //Try to insert your entity by calling persist method    
    }
    catch(EntityExistsException e){
        //Entity you are trying to insert already exist, then call merge method
    }
}

回答by akash777.sharma

This error occurs when you try to update a domain object that already exists, like

当您尝试更新已存在的域对象时会发生此错误,例如

User user=UserDao.getUserById(1);
session.save(user);

Hibernate will treat it like saving a new object and it will find that a duplicate object exists.

Hibernate 会将其视为保存新对象,并且会发现存在重复的对象。

Before updating your object first load it from hibernate, like

在更新您的对象之前,首先从休眠状态加载它,例如

User updatedUser=(User)session.load(User.class, 1);
updatedUser.setName("user name");
session.saveOrUpdate(updatedUser);