为什么 JavaScript 负数并不总是对或错?

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时间:2020-08-23 05:27:36  来源:igfitidea点击:

Why are JavaScript negative numbers not always true or false?

javascriptboolean-logicbitwise-operators

提问by Ollie Edwards

-1 == true;        // false
-1 == false        // false
-1 ? true : false; // true

Can anyone explain the above output? I know I could work round this by comparing to 0 but I'm interested. I'd expect at least one of the sloppy equals statements to be true as they do implicit type conversion, and I certainly didn't expect the ternary to come up with a totally different result.

谁能解释一下上面的输出?我知道我可以通过与 0 进行比较来解决这个问题,但我很感兴趣。我希望至少有一个草率的 equals 语句在执行隐式类型转换时为真,而且我当然没想到三元会得出完全不同的结果。

回答by Andy E

In the first two cases, the boolean is cast to a number - 1 for trueand 0 for false. In the final case, it is a number that is cast to a boolean and any number except for 0 and NaN will cast to true. So your test cases are really more like this:

在前两种情况下,布尔值被强制转换为一个数字 - 1 表示true, 0 表示false。在最后一种情况下,它是一个转换为布尔值的数字,除 0 和 NaN 之外的任何数字都将转换为true。所以你的测试用例真的更像这样:

-1 == 1; // false
-1 == 0; // false
true ? true : false; // true

The same would be true of any number that isn't 0 or 1.

任何不是 0 或 1 的数字也是如此。

For more detail, read the ECMAScript documentation. From the 3rd edition [PDF], section 11.9.3 The Abstract Equality Comparison Algorithm:

有关更多详细信息,请阅读 ECMAScript 文档。从第3 版 [PDF],第11.9.3抽象平等比较算法

19. If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).

19. 如果 Type(y) 是布尔值,则返回比较结果 x == ToNumber(y)。

It's worth giving the full algorithm a read because other types can cause worse gotchas.

值得阅读完整的算法,因为其他类型可能会导致更糟糕的问题。

回答by Amber

In most systems, non-zero values are considered a true value, but that doesn't necessarily mean that they are the sametrue value as true. Thus, -1 == truedoesn't necessarily hold, but -1can still be considered a true value since it is non-zero.

在大多数系统中,非零值被视为真值,但这并不一定意味着它们与 的真值相同true。因此,-1 == true不一定成立,但-1仍可被视为真值,因为它不为零。

Really, though, you shouldn't be comparing integers to booleans if you can avoid it.

但是,实际上,如果可以避免的话,您不应该将整数与布尔值进行比较。

回答by AStanton

When evaluated as a test condition, integers like -1, 5 and 17,000,000, all return Boolean true, because they logically evaluate to true, e.g.

当作为测试条件评估时,像 -1、5 和 17,000,000 这样的整数都返回布尔值 true,因为它们在逻辑上评估为 true,例如

if(-1) {
    "This is true";
}
else {
    "This is false";
}
=> "This is true";

(Note: 0 logically evaluates to false)

(注意:0 逻辑上评估为假)

Using the "?" operator does what this code just does. It passes the first argument as a condition in an ifstatement, passes the second argument as the truecase, and passes the third argument as the falsecase.

使用 ”?” 运算符执行此代码所做的操作。它将第一个参数作为if语句中的条件传递,将第二个参数作为情况传递,并将第三个参数作为情况传递。

Hence the third result.

因此第三个结果。



However, these integers are not of the same typeas true.

但是,这些整数与true 的类型不同

Trueis of type Boolean, -1, 5 and 17,000,000are of type Integer.

True属于Boolean类型,-1、5 和 17,000,000属于Integer类型。

The comparison '==' is strict, in terms of type comparison. Even two things have the same "value", but not the same type, the "==" operator returns false:

就类型比较而言,比较 '==' 是严格的。即使两件事具有相同的“值”,但类型不同,“==”运算符也会返回false

if(6 == true) {
    "This is true";
}
else {
    "This is false";
}
=> "This is false";

Even the following will return false, because "true"is of type Stringand trueis of type Boolean:

即使以下内容也将返回 false,因为"true"属于String类型,而true属于Boolean类型:

if("true" == true) {
    "This is true";
}
else {
    "This is false";
}
=> "This is false";

Hence, the first two results.

因此,前两个结果。



Note: If you'd like to compare values irregardless of type, use the "===" operator:

注意:如果您想比较任何类型的值,请使用“===”运算符:

if(6 === true) {
    "This is true";
}
else {
    "This is false";
}
=> "This is true";

and also,

并且,

if("true" === true) {
    "This is true";
}
else {
    "This is false";
}
=> "This is true";


Hope this helps!


希望这可以帮助!