jQuery 如何根据值检查复选框?
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How can I check checkboxes based on values?
提问by Paul
I am returning a JSON data structure that I split and populate my array like so:
我正在返回一个 JSON 数据结构,我将其拆分并填充我的数组,如下所示:
var arrayValues = data.contents.split('|');
// arrayValues = 1,3,4
How can I check the corresponding checkboxes based on the array values?
如何根据数组值检查相应的复选框?
My HTML looks like this:
我的 HTML 如下所示:
<div id="divID">
<input type="checkbox" name="test" value="1" /> Test 1<br />
<input type="checkbox" name="test" value="2" /> Test 2<br />
<input type="checkbox" name="test" value="3" /> Test 3<br />
<input type="checkbox" name="test" value="4" /> Test 4<br />
<input type="checkbox" name="test" value="5" /> Test 5<br />
</div>
回答by ShankarSangoli
Try this using attribute selector
使用属性选择器试试这个
$.each(arrayValues, function(i, val){
$("input[value='" + val + "']").prop('checked', true);
});
回答by John Hartsock
Javascript
Javascript
$.each(arrayValues, function (index, value) {
$('input[name="test"][value="' + value.toString() + '"]').prop("checked", true);
});
回答by Christophe Quintard
Simpler :
更简单:
$('input[name="test"]').val(arrayValues);
This will check the values from the array and deselect the others.
这将检查数组中的值并取消选择其他值。
From the JQuery's doc : http://api.jquery.com/val/
来自 JQuery 的文档:http: //api.jquery.com/val/
val() allows you to pass an array of element values. This is useful when working on a jQuery object containing elements like <input type="checkbox">, <input type="radio">, and <option>s inside of a <select>. In this case, the inputs and the options having a value that matches one of the elements of the array will be checked or selected while those having a value that doesn't match one of the elements of the array will be unchecked or unselected, depending on the type.
val() 允许您传递元素值数组。这在处理包含 <input type="checkbox">、<input type="radio"> 和 <option> 等元素的 jQuery 对象时很有用。在这种情况下,将检查或选择具有与数组元素之一匹配的值的输入和选项,而具有与数组元素之一不匹配的值的输入和选项将被取消选中或取消选择,具体取决于在类型上。
回答by JohnP
You can loop through your array and do an attribute search on jQuery
您可以遍历数组并在 jQuery 上进行属性搜索
var i = 0;
while (arrayValues.length < i) {
var val = arrayValues[i];
$('#divID input[value="' + val + '"]').prop('checked', 'checked');
i++;
}
回答by Smamatti
Okay took me a moment to sort out my error in the code. I guess this question is answered by ShankarSangolinow.
好的,我花了一点时间来整理代码中的错误。我想这个问题现在由ShankarSangoli回答。
I hope you don't mind me posting my solution either way. I'm just curious if this is worse for performance etc.
我希望你不介意我以任何方式发布我的解决方案。我只是好奇这是否对性能等更糟。
var arrayValues = new Array(1,3,4);
$('#divID input').filter(function(){
return ($.inArray( parseInt($(this).attr('value')), arrayValues)) != -1;
}).attr('checked', 'checked');