javascript 使用 $.post 将 JS 变量发送到 PHP 脚本
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Using $.post to send JS variables to PHP script
提问by user2177629
I am trying to send Javascript variables over to a PHP script for updating scores of a quiz game. I've looked up the shorthand method of doing this, which is $.post, but I am unable to retrieve the values in the PHP script. I am fairly unfamiliar which JS and require help as to what I am doing wrong.
我正在尝试将 Javascript 变量发送到 PHP 脚本以更新测验游戏的分数。我查找了执行此操作的速记方法，即 $.post，但我无法检索 PHP 脚本中的值。我相当不熟悉哪个 JS 并且需要关于我做错了什么的帮助。
Here is the Javascript
这是Javascript
function updatescore(){
var thisgamemarks= 2300;
var thequizid = 5;
$.post("updatemark.php", { quizidvalue: thequizid, newmarkvalue: thisgamemarks } );
}
And the PHP
和 PHP
$studentnewmark = $POST['newmarkvalue'];
$thisquizid = $POST['quizidvalue'];
$thisstudentid = $_SESSION['studentid'];
回答by tay10r
type $_POST instead of $POST. also, on a windows based machine, you can use ctrl + shift + j to debug a js script - which will help if if there's any problems with your code. but, the js code you have shown us looks perfectly fine.
键入 $_POST 而不是 $POST。此外，在基于 Windows 的机器上，您可以使用 ctrl + shift + j 来调试 js 脚本 - 如果您的代码有任何问题，这将有所帮助。但是，您向我们展示的 js 代码看起来非常好。
回答by Touch
Yes. As suggest use the $_POST instead of $POST and try putting the "quizidvalue" in the javascript inside quotations. It might help. Just a thought. It's how I always do it.
是的。建议使用 $_POST 而不是 $POST 并尝试将“quizidvalue”放在 javascript 中的引号内。它可能会有所帮助。只是一个想法。这就是我总是这样做的方式。
