Linux 如何比较两个目录的大小？
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How to compare the size of two directories?
提问by rafak
I want to compare the total size of two directories dir1and dir2on different file-systems so that if diff -r dir1 dir2returns 0then the total sizes will be equal. The ducommand returns the disk usage, and its option --apparent-sizedoesn't solve the problem. I now use something like
我想比较两个目录dir1和dir2不同文件系统上的总大小，以便如果diff -r dir1 dir2返回，0那么总大小将相等。该du命令返回磁盘使用情况，其选项--apparent-size不能解决问题。我现在使用类似的东西
find dir1 ! -type d |xargs wc -c |tail -1
to know an approximation of dir1's size. Is there a better solution?
了解 dir1 大小的近似值。有更好的解决方案吗？
edit:
for example, I have (diff -r dir1 dir2returns 0: they are equal):
编辑：例如，我有（diff -r dir1 dir2返回 0：它们相等）：
du -s dir1 --> 540
du -s dir2 --> 166
du -sb dir1 --> 250815 (the -b option is equivalent to --apparent-size -B1)
du -sb dir2 --> 71495
find dir1 ! -type d |xargs wc -c --> 62399
find dir2 ! -type d |xargs wc -c --> 62399
回答by Paused until further notice.
If your version of findhas -printfyou may find this to be quite a bit faster.
如果您的版本find有，-printf您可能会发现这要快得多。
find dir1 ! -type d -printf "%s\n" | awk '{sum += } END{print sum}'
There are at least two ways to avoid scientific notation for outputting large numbers in AWK.
至少有两种方法可以避免在 AWK 中输出大量数字的科学记数法。
END {OFMT = "%.0f"; print sum}
END {printf "%.0f\n", sum}
The .0truncates the decimal places since we're really dealing with an integer and gawk's %dseems to incorrectly act like %gin version 3.1.5 (but not 3.1.6 and later).
该.0截断小数位，因为我们真正处理的是一个整数，GAWK的%d似乎错误地像%g在3.1.5版本（但不是3.1.6或更高版本）。
However, from the gawkdocumentation:
但是，从gawk文档中：
NOTE: When using the integer format-control letters for values that are outside the range of the widest C integer type, 'gawk' switches to the '%g' format specifier.
注意：当对最宽的 C 整数类型范围之外的值使用整数格式控制字母时，'gawk' 切换到 '%g' 格式说明符。
Beware of exceeding the maximum integer for your system/version of AWK.
当心超过系统/AWK 版本的最大整数。
回答by zjhui
i can't know what you want clearly. Maybe you want this?diff <(du -sh dir1) <(du -sh dir2)
我无法清楚地知道你想要什么。也许你想要这个？diff <(du -sh dir1) <(du -sh dir2)
