Python 类型错误：强制转换为 Unicode：需要字符串或缓冲区，找到列表
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TypeError: coercing to Unicode: need string or buffer, list found
提问by user3234810
I'm trying to get a data parsing script up and running. It works as far as the data manipulation is concerned. What I'm trying to do is set this up so I can enter multiple user defined CSV's with a single command.
我正在尝试启动并运行数据解析脚本。就数据操作而言，它是有效的。我想要做的是设置它，以便我可以使用单个命令输入多个用户定义的 CSV。
e.g.
例如
> python script.py One.csv Two.csv Three.csv
If you have any advice on how to automate the naming of the output CSV so that if input = test.csv, output = test1.csv, I'd appreciate that as well.
如果您对如何自动命名输出 CSV 有任何建议，以便 if input = test.csv, output = test1.csv，我也将不胜感激。
Getting
得到
TypeError: coercing to Unicode: need string or buffer, list found
for the line
对于线
for line in csv.reader(open(args.infile)):
My code:
我的代码：
import csv
import pprint
pp = pprint.PrettyPrinter(indent=4)
res = []
import argparse
parser = argparse.ArgumentParser()
#parser.add_argument("infile", nargs="*", type=str)
#args = parser.parse_args()
parser.add_argument ("infile", metavar="CSV", nargs="+", type=str, help="data file")
args = parser.parse_args()
with open("out.csv","wb") as f:
output = csv.writer(f)
for line in csv.reader(open(args.infile)):
for item in line[2:]:
#to skip empty cells
if not item.strip():
continue
item = item.split(":")
item[1] = item[1].rstrip("%")
print([line[1]+item[0],item[1]])
res.append([line[1]+item[0],item[1]])
output.writerow([line[1]+item[0],item[1].rstrip("%")])
I don't really understand what is going on with the error. Can someone explain this in layman's terms?
我真的不明白错误是怎么回事。有人可以用外行的术语解释这一点吗？
Bear in mind I am new to programming/python as a whole and am basically learning alone, so if possible could you explain what is going wrong/how to fix it so I can note it for future reference.
请记住，我是整个编程/python 的新手，基本上是一个人学习，所以如果可能的话，你能解释一下出了什么问题/如何修复它，以便我可以记录下来以备将来参考。
采纳答案by Martijn Pieters
args.infileis a listof filenames, not one filename. Loop over it:
args.infile是一个文件名列表，而不是一个文件名。循环它：
for filename in args.infile:
base, ext = os.path.splitext(filename)
with open("{}1{}".format(base, ext), "wb") as outf, open(filename, 'rb') as inf:
output = csv.writer(outf)
for line in csv.reader(inf):
Here I used os.path.splitext()to split extension and base filename so you can generate a new output filename adding 1to the base.
在这里，我曾经os.path.splitext()拆分扩展名和基本文件名，以便您可以生成添加1到基本文件名的新输出文件名。
回答by Wooble
If you specify an nargsargument to .add_argument, the argument will always be returned as a list.
如果您为 指定nargs参数.add_argument，则该参数将始终作为列表返回。
Assuming you want to deal with all of the files specified, loop through that list:
假设您要处理指定的所有文件，请遍历该列表：
for filename in args.infile:
for line in csv.reader(open(filename)):
for item in line[2:]:
#to skip empty cells
[...]
Or if you really just want to be able to specify a single file; just get rid of nargs="+".
或者，如果您真的只想指定一个文件；刚刚摆脱nargs="+"。
