json 如何通过 Swift 发送 POST 请求?
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/43907542/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to send a POST request through Swift?
提问by user2775042
I have my controller like this -
我有这样的控制器 -
def create
if (@user = User.find_by_email(params[:email])) && @user.valid_password?(params[:password])
render json: @user.as_json(only: [:email,:authentication_token]),status: :created
else
render json:('Unauthorized Access')
end
end
When I use Postman to make this request, I choose Body, and form data and adds in the email and password. And this WORKS
当我使用 Postman 发出此请求时,我选择 Body,并形成数据并添加电子邮件和密码。这有效
How to use swift to do the same? This is what I have tried
如何使用swift来做同样的事情?这是我尝试过的
let url = URL(string: "http://localhost:3000/api/v1/user_serialized/")
let config = URLSessionConfiguration.default
let request = NSMutableURLRequest(url: url!)
request.httpMethod = "POST"
let bodyData = "[email protected]&password=Test1234"
request.httpBody = bodyData.data(using: String.Encoding.utf8);
let session = URLSession(configuration: config)
let task = session.dataTask(with: url! as URL, completionHandler: {(data, response, error) in
let json = JSON(data:data!)
debugPrint(json)
})
task.resume()
采纳答案by ndreisg
I think you should pass your request instead of the url to session.dataTask
我认为您应该将您的请求而不是 url 传递给 session.dataTask
here is how my code looks like:
这是我的代码的样子:
private let url = URL(string: "http://example.com/")!
func httpPost(jsonData: Data) {
if !jsonData.isEmpty {
var request = URLRequest(url: url)
request.httpMethod = "POST"
request.httpBody = jsonData
URLSession.shared.getAllTasks { (openTasks: [URLSessionTask]) in
NSLog("open tasks: \(openTasks)")
}
let task = URLSession.shared.dataTask(with: request, completionHandler: { (responseData: Data?, response: URLResponse?, error: Error?) in
NSLog("\(response)")
})
task.resume()
}
}
回答by Balaji Galave
I have made a Custom HTTP class where we can sent url, parameter and we will get Data from API. Below is the class.
我已经创建了一个自定义 HTTP 类,我们可以在其中发送 url、参数,我们将从 API 获取数据。下面是班级。
import Foundation
//HTTP Methods
enum HttpMethod : String {
case GET
case POST
case DELETE
case PUT
}
class HttpClientApi: NSObject{
//TODO: remove app transport security arbitary constant from info.plist file once we get API's
var request : URLRequest?
var session : URLSession?
static func instance() -> HttpClientApi{
return HttpClientApi()
}
func makeAPICall(url: String,params: Dictionary<String, Any>?, method: HttpMethod, success:@escaping ( Data? ,HTTPURLResponse? , NSError? ) -> Void, failure: @escaping ( Data? ,HTTPURLResponse? , NSError? )-> Void) {
request = URLRequest(url: URL(string: url)!)
logging.print("URL = \(url)")
if let params = params {
let jsonData = try? JSONSerialization.data(withJSONObject: params, options: .prettyPrinted)
request?.setValue("application/json", forHTTPHeaderField: "Content-Type")
request?.httpBody = jsonData//?.base64EncodedData()
//paramString.data(using: String.Encoding.utf8)
}
request?.httpMethod = method.rawValue
let configuration = URLSessionConfiguration.default
configuration.timeoutIntervalForRequest = 30
configuration.timeoutIntervalForResource = 30
session = URLSession(configuration: configuration)
//session?.configuration.timeoutIntervalForResource = 5
//session?.configuration.timeoutIntervalForRequest = 5
session?.dataTask(with: request! as URLRequest) { (data, response, error) -> Void in
if let data = data {
if let response = response as? HTTPURLResponse, 200...299 ~= response.statusCode {
success(data , response , error as? NSError)
} else {
failure(data , response as? HTTPURLResponse, error as? NSError)
}
}else {
failure(data , response as? HTTPURLResponse, error as? NSError)
}
}.resume()
}
}
Now you can refer below code to get how to make an API call.
现在您可以参考以下代码来了解如何进行 API 调用。
var paramsDictionary = [String:Any]()
paramsDictionary["username"] = "BBB"
paramsDictionary["password"] = "refef"
HttpClientApi.instance().makeAPICall(url: "Your URL", params:paramsDictionary, method: .POST, success: { (data, response, error) in
// API call is Successfull
}, failure: { (data, response, error) in
// API call Failure
})
回答by Rouny
Here is the Example of POST API for calling Login API with parameters "emailaddress" and "password" with userEmailID and Userpassword as two strings holding values for email and password respectively.
下面是使用参数“emailaddress”和“password”调用登录 API 的 POST API 示例,其中 userEmailID 和 Userpassword 作为两个字符串分别保存电子邮件和密码的值。
You can call this POST API anywhere in your view controller, as given below:
您可以在视图控制器的任何位置调用此 POST API,如下所示:
self.postLoginCall(url: "Your post method url")example: self.postLoginCall(url: "http://1.0.0.1/api/login.php")
self.postLoginCall(url: "Your post method url")示例:self.postLoginCall(url: " http://1.0.0.1/api/login.php")
func postLoginCall(url : String){
let request = NSMutableURLRequest(url: NSURL(string: url)! as URL)
request.httpMethod = "POST"
let postString = "emailaddress=\(userEmailID!)&password=\(Userpassword!)"
print(postString)
request.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
request.httpBody = postString.data(using: String.Encoding.utf8)
let task = URLSession.shared.dataTask(with: request as URLRequest) { data, response, error in
guard error == nil && data != nil else { // check for fundamental networking error
print("error=\(error)")
return
}
do {
if let responseJSON = try JSONSerialization.jsonObject(with: data!) as? [String:AnyObject]{
print(responseJSON)
print(responseJSON["status"]!)
self.response1 = responseJSON["status"]! as! Int
print(self.response1)
//Check response from the sever
if self.response1 == 200
{
OperationQueue.main.addOperation {
//API call Successful and can perform other operatios
print("Login Successful")
}
}
else
{
OperationQueue.main.addOperation {
//API call failed and perform other operations
print("Login Failed")
}
}
}
}
catch {
print("Error -> \(error)")
}
}
task.resume()
}


