ios 获取推送通知的设备令牌
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/8798725/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Get device token for push notification
提问by jagzzz
I am working on push notifications. I wrote the following code for fetching a device token.
我正在处理推送通知。我编写了以下代码来获取设备令牌。
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
// Override point for customization after application launch.
// Add the view controller's view to the window and display.
[self.window addSubview:viewController.view];
[self.window makeKeyAndVisible];
NSLog(@"Registering for push notifications...");
[[UIApplication sharedApplication] registerForRemoteNotificationTypes:
(UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];
return YES;
}
- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken {
NSString *str = [NSString stringWithFormat:@"Device Token=%@",deviceToken];
NSLog(@"This is device token%@", deviceToken);
}
- (void)application:(UIApplication *)app didFailToRegisterForRemoteNotificationsWithError:(NSError *)err {
NSString *str = [NSString stringWithFormat: @"Error: %@", err];
NSLog(@"Error %@",err);
}
I am able to run application on device successfully but not able to get the device id on console.
我能够在设备上成功运行应用程序，但无法在控制台上获取设备 ID。
I have no issues with certification and provisioning profiles.
我对认证和配置文件没有任何问题。
回答by Wasif Saood
NOTE:The below solution no longer workson iOS 13+ devices - it will return garbage data.
注意：以下解决方案不再适用于 iOS 13+ 设备 -它将返回垃圾数据。
Please use following code instead:
请改用以下代码：
+ (NSString *)hexadecimalStringFromData:(NSData *)data
{
NSUInteger dataLength = data.length;
if (dataLength == 0) {
return nil;
}
const unsigned char *dataBuffer = (const unsigned char *)data.bytes;
NSMutableString *hexString = [NSMutableString stringWithCapacity:(dataLength * 2)];
for (int i = 0; i < dataLength; ++i) {
[hexString appendFormat:@"%02x", dataBuffer[i]];
}
return [hexString copy];
}
Solution that worked prior to iOS 13:
在 iOS 13 之前运行的解决方案：
Objective-C
目标-C
- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
{
NSString *token = [[deviceToken description] stringByTrimmingCharactersInSet: [NSCharacterSet characterSetWithCharactersInString:@"<>"]];
token = [token stringByReplacingOccurrencesOfString:@" " withString:@""];
NSLog(@"this will return '32 bytes' in iOS 13+ rather than the token", token);
}
Swift 3.0
斯威夫特 3.0
func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data)
{
let tokenString = deviceToken.reduce("", {- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
[self.window addSubview:viewController.view];
[self.window makeKeyAndVisible];
NSLog(@"Registering for push notifications...");
[[UIApplication sharedApplication] registerForRemoteNotificationTypes:
(UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];
return YES;
}
- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken {
NSString *str = [NSString stringWithFormat:@"Device Token=%@",deviceToken];
NSLog(@"%@", str);
}
- (void)application:(UIApplication *)app didFailToRegisterForRemoteNotificationsWithError:(NSError *)err {
NSString *str = [NSString stringWithFormat: @"Error: %@", err];
NSLog(@"%@",str);
}
+ String(format: "%02X", )})
print("this will return '32 bytes' in iOS 13+ rather than the token \(tokenString)")
}
回答by Bkillnest
To get Token Device you can do by some steps:
要获得令牌设备，您可以通过以下步骤进行：
1) Enable APNS (Apple Push Notification Service) for both Developer Certification and Distribute Certification, then redownload those two file.
1) 为开发者认证和分发认证启用 APNS（Apple 推送通知服务），然后重新下载这两个文件。
2) Redownload both Developer Provisioning and Distribute Provisioning file.
2) 重新下载 Developer Provisioning 和 Distribute Provisioning 文件。
3) In Xcode interface: setting provisioning for PROJECT and TARGETS with two file provisioning have download.
3）在Xcode界面：设置PROJECT和TARGETS的provisioning，两个文件provisioning已经下载。
4) Finally, you need to add the code below in AppDelegate file to get Token Device (note: run app in real device).
4）最后，需要在AppDelegate文件中添加如下代码来获取Token Device（注意：在真机上运行app）。
// credit to NSHipster (see link above)
// format specifier produces a zero-padded, 2-digit hexadecimal representation
let deviceTokenString = deviceToken.map { String(format: "%02x", // Prepare the Device Token for Registration (remove spaces and < >)
NSString *devToken = [[[[deviceToken description]
stringByReplacingOccurrencesOfString:@"<"withString:@""]
stringByReplacingOccurrencesOfString:@">" withString:@""]
stringByReplacingOccurrencesOfString: @" " withString: @""];
NSString *str = [NSString
stringWithFormat:@"Device Token=%@",devToken];
UIAlertView *alertCtr = [[[UIAlertView alloc] initWithTitle:@"Token is " message:devToken delegate:self cancelButtonTitle:nil otherButtonTitles: nil] autorelease];
[alertCtr show];
NSLog(@"device token - %@",str);
) }.joined()
回答by cdstamper
Using descriptionas many of these answers suggest is the wrong approach- even if you get it to work, it will break in iOS 13+.
使用description这些答案中的许多建议是错误的方法- 即使你让它工作，它也会在 iOS 13+ 中崩溃。
Instead you should ensure you use the actual binary data, not simply a description of it. Andrey Gagan addressed the Objective C solution quite well, but fortunately it's much simpler in swift:
相反，您应该确保使用实际的二进制数据，而不仅仅是对它的描述。Andrey Gagan 很好地解决了 Objective C 解决方案，但幸运的是它在 swift 中要简单得多：
Swift 4.2works in iOS 13+
Swift 4.2适用于iOS 13+
var token = deviceToken.description.stringByTrimmingCharactersInSet(NSCharacterSet(charactersInString: "<>"))
token = token.stringByReplacingOccurrencesOfString(" ", withString: "")
print("Token is \(token)")
回答by Nimit Parekh
Following code is use for the retrive the device token.
以下代码用于检索设备令牌。
let deviceTokenString = deviceToken.map { String(format: "%02.2hhx", #if __IPHONE_OS_VERSION_MAX_ALLOWED >= 80000
if ([UIApplication respondsToSelector:@selector(registerUserNotificationSettings:)]) {
UIUserNotificationSettings *settings = [UIUserNotificationSettings settingsForTypes:UIUserNotificationTypeBadge|UIUserNotificationTypeAlert|UIUserNotificationTypeSound
categories:nil];
[[UIApplication sharedApplication] registerUserNotificationSettings:settings];
[[UIApplication sharedApplication] registerForRemoteNotifications];
} else {
[[UIApplication sharedApplication] registerForRemoteNotificationTypes:
UIRemoteNotificationTypeBadge |
UIRemoteNotificationTypeAlert |
UIRemoteNotificationTypeSound];
}
#else
[[UIApplication sharedApplication] registerForRemoteNotificationTypes:
UIRemoteNotificationTypeBadge |
UIRemoteNotificationTypeAlert |
UIRemoteNotificationTypeSound];
#endif
) }.joined()
回答by Antoine
And the Swift version of the Wasif's answer:
以及 Wasif 答案的 Swift 版本：
Swift 2.x
斯威夫特 2.x
- (void)application:(UIApplication *)app didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
{
NSUInteger dataLength = deviceToken.length;
if (dataLength == 0) {
return;
}
const unsigned char *dataBuffer = (const unsigned char *)deviceToken.bytes;
NSMutableString *hexString = [NSMutableString stringWithCapacity:(dataLength * 2)];
for (int i = 0; i < dataLength; ++i) {
[hexString appendFormat:@"%02x", dataBuffer[i]];
}
NSLog(@"APN token:%@", hexString);
}
Update for Swift 3
Swift 3 更新
+ (NSString *)stringFromDeviceToken:(NSData *)deviceToken {
NSUInteger length = deviceToken.length;
if (length == 0) {
return nil;
}
const unsigned char *buffer = deviceToken.bytes;
NSMutableString *hexString = [NSMutableString stringWithCapacity:(length * 2)];
for (int i = 0; i < length; ++i) {
[hexString appendFormat:@"%02x", buffer[i]];
}
return [hexString copy];
}
回答by Nilesh
If you are still not getting device token, try putting following code so to register your device for push notification.
如果您仍然没有获得设备令牌，请尝试输入以下代码以便注册您的设备以接收推送通知。
It will also work on ios8 or more.
它也适用于 ios8 或更高版本。
func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
let deviceTokenString = deviceToken.reduce("", {func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
print("\(deviceToken.reduce("") { ##代码## + String(format: "%02.2hhx", arguments: []) })")
}
+ String(format: "%02X", )})
print("Device token: \(deviceTokenString)")
}
回答by Jake Cronin
Objective C for iOS 13+, courtesy of Wasif Saood's answer
iOS 13+ 的 Objective C，由 Wasif Saood 的回答提供
Copy and paste below code into AppDelegate.m to print the device APN token.
将以下代码复制并粘贴到 AppDelegate.m 中以打印设备 APN 令牌。
##代码##回答by Andrey Gagan
Starting from iOS 13 Apple has changed [deviceToken description]output. Now it is like this {length=32,bytes=0x0b8823aec3460e1724e795cba45d22e8...af8c09f971d0dabc}which is incorrect for device token.
从 iOS 13 开始，Apple 更改了[deviceToken description]输出。现在它是这样的，这{length=32,bytes=0x0b8823aec3460e1724e795cba45d22e8...af8c09f971d0dabc}对于设备令牌是不正确的。
I suggest to use this code snippet to resolve a problem:
我建议使用此代码片段来解决问题：
##代码##It will work for iOS13 and lower.
它适用于 iOS13 及更低版本。
回答by Sedat Y
Get device token in Swift 3
在 Swift 3 中获取设备令牌
##代码##回答by vfn
In your AppDelegate, in the didRegisterForRemoteNotificationsWithDeviceTokenmethod:
在您的 AppDelegate 中，在didRegisterForRemoteNotificationsWithDeviceToken方法中：
Updated for Swift:
为 Swift 更新：
##代码##