xcode .xcconfig？如何设置环境变量
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.xcconfig? How to set environment variables
提问by Dean
I'm new to Xcode.
我是 Xcode 的新手。
I spent the last two days trying to figure out how to test my app on my iPhone which accesses a web service. On the simulator I can use a hard-coded 'localhost' variable, but I don't want to hardcode all the configuration settings.
在过去的两天里，我试图弄清楚如何在访问网络服务的 iPhone 上测试我的应用程序。在模拟器上，我可以使用硬编码的“localhost”变量，但我不想对所有配置设置进行硬编码。
I'm using Swift + Xcode 6 but I think this is the same process as Xcode 5.
我正在使用 Swift + Xcode 6，但我认为这与 Xcode 5 的过程相同。
I looked through lots of articles and I think I'm supposed to use .xcconfig, but it's very unclear.
我浏览了很多文章，我认为我应该使用 .xcconfig，但它很不清楚。
For example, I created a Environment.xcconfigfile. I populated it with
例如，我创建了一个Environment.xcconfig文件。我填充了它
API_BASE_URL = "http://localhost:4000/api/v1"
I then went into Project -> Info and set the Debug configuration file to Environment.
然后我进入 Project -> Info 并将调试配置文件设置为Environment.
I then tried to access the variable in code via ${API_BASE_URL}but I get Use of unresolved identifier 'API_BASE_URL'.
然后我尝试通过代码访问变量，${API_BASE_URL}但我得到Use of unresolved identifier 'API_BASE_URL'.
This is extremely frustrating. Any ideas?
这是非常令人沮丧的。有任何想法吗？
回答by kas-kad
- Setup config hierarchy in case you have pods configs:
- 如果您有 pods 配置，请设置配置层次结构：
OR if you haven't any pods at all, the Configurations hierarchy gonna look like this:
或者，如果您根本没有任何 Pod，则配置层次结构将如下所示：
Create all the key-value pairs for each config file (in this case there are 3 config files for dev/adhoc/appstore builds). Each config file has same set of keys:
Add each key to the generator:
Then just use the keys in your code :
为每个配置文件创建所有键值对（在本例中，有 3 个用于 dev/adhoc/appstore 构建的配置文件）。每个配置文件都有相同的一组键：
将每个键添加到生成器：
然后只需使用代码中的键：
PS: the keys generated this way are also recognizable in .swift files (make sure you have a bridging header in your Swift project, even though you don't use obj-c sources and it will be empty).
PS：以这种方式生成的键也可以在 .swift 文件中识别（确保你的 Swift 项目中有一个桥接头，即使你不使用 obj-c 源并且它会是空的）。
UPDATE for Swift 2.2: doesn't work anymoreSwift 2.2: GCC_PREPROCESSOR_DEFINITIONS constants no longer imported
Swift 2.2 更新：不再工作Swift 2.2：GCC_PREPROCESSOR_DEFINITIONS 常量不再导入
回答by NRitH
You don't want .xcconfig; that stores settings for Xcode. Instead, you want a property list (.plist) file. To do so, hit command-Nto create a new file, then select iOS > Resources > Property List. Use the plist editor to add keys, values, and value types. Then load your properties by adding these lines somewhere in your app:
你不想要.xcconfig; 存储 Xcode 的设置。相反，您需要一个属性列表 ( .plist) 文件。为此，请点击command-N创建一个新文件，然后选择iOS > Resources > Property List。使用 plist 编辑器添加键、值和值类型。然后通过在您的应用程序中的某处添加这些行来加载您的属性：
if let filePath = NSBundle.mainBundle().pathForResource("Latin Conjugations", ofType:"plist") {
let plist = NSDictionary(contentsOfFile:filePath)
}
You can then access your properties via the plist dictionary like you would any other dictionary value. Note that it's not a Swift Dictionary, since that doesn't have a constructor that takes a file path to load.
然后，您可以像访问任何其他字典值一样通过 plist 字典访问您的属性。请注意，它不是 Swift Dictionary，因为它没有接受文件路径加载的构造函数。
Updated 10/21/2015:This answer is now Swift 2.0-compliant. pathForResource()now returns an Optional.
2015 年 10 月 21 日更新：此答案现在符合 Swift 2.0。pathForResource()现在返回一个可选。
