出现点和下划线时搜索并替换为 sed
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Search and replace with sed when dots and underscores are present
提问by algorithmicCoder
How do I replace foo. with foo_ with sed simply running
我如何替换 foo. 与 foo_ 与 sed 简单地运行
sed 's/foo./foo_/g' file.php
doesn't work. Thanks!
不起作用。谢谢！
回答by rid
Escape the .:
逃脱.：
sed 's/foo\./foo_/g' file.php
Example:
例子：
~$ cat test.txt
foo.bar
~$ sed 's/foo\./foo_/g' test.txt
foo_bar
回答by August Karlstrom
You need to escape the dot - an unescaped dot will match any character after foo.
您需要对点进行转义 - 未转义的点将匹配 foo 之后的任何字符。
sed 's/foo\./foo_/g'
回答by sashang
Escape the dot with a \
用 \ 转义点
sed 's/foo\./foo_/g' file.php
If you find the combination of / and \ confusing you can use another 'separator' character
如果您发现 / 和 \ 的组合令人困惑，您可以使用另一个“分隔符”字符
sed 's#foo\.#foo_#g
The 2nd character after the s can be anything and sed will use that character as a separator.
s 之后的第二个字符可以是任何字符，sed 将使用该字符作为分隔符。
回答by Paul S
Interestingly, if you want to search for and replace just the dot, you have to put the dot in a character set. Escaping just the dot alone in a sed command for some reason doesn't work. The dot is still expanded to a single character wild card.
有趣的是，如果您只想搜索和替换点，则必须将点放入字符集中。由于某种原因，仅在 sed 命令中单独转义点是行不通的。点仍然扩展为单个字符通配符。
$ bash --version # Ubuntu Lucid (10.04)
GNU bash, version 4.1.5(1)-release (x86_64-pc-linux-gnu)
GNU bash，版本 4.1.5(1)-release (x86_64-pc-linux-gnu)
$ echo aa.bb.cc | sed s/\./-/g # replaces all characters with dash
'--------'
'--------'
$ echo aa.bb.cc | sed s/[.]/-/g # replaces the dots with a dash
aa-bb-cc
aa-bb-cc
With the addition of leading characters in the search, the escape works.
通过在搜索中添加前导字符，转义符起作用了。
$ echo foo. | sed s/foo\./foo_/g # works
foo_
foo_
Putting the dot in a character set of course also works.
将点放在字符集中当然也有效。
$ echo foo. | sed s/foo[.]/foo_/g # also works
foo_
foo_
-- Paul
——保罗
回答by jfg956
For myself, sed 's/foo\./foo_/g'is working. But you can also try:
对于我自己，sed 's/foo\./foo_/g'正在工作。但你也可以尝试：
sed -e 's/foo\./foo_/g'
and
和
sed -e "s/foo\./foo_/g"
and
和
sed 's/foo[.]/foo_/g'
