使用 PHP 匹配 HTML <p> 标签的正则表达式
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Regular Expression to Match HTML <p> tag using PHP
提问by Atif Mohammed Ameenuddin
I have some content like this
我有一些这样的内容
<p>some content, paragraph 1</p>
<p>some content, paragraph 2</p>
<p>some content, paragraph 3</p>
I would like to return the first paragraph i.e.
我想返回第一段即
<p>some content, paragraph 1</p>
Can anyone assist me with the regex code?'<p>(.*.)</p>'doesnt seem to work
任何人都可以帮助我使用正则表达式代码吗？'<p>(.*.)</p>'似乎不起作用
回答by SubniC
you can do it this way:
你可以这样做：
if (preg_match('%(<p[^>]*>.*?</p>)%i', $subject, $regs)) {
$result = $regs[1];
} else {
$result = "";
}
You test your string against the regular expresion, if there are some match, you get the first and only the first one, if there are none $result will be an empty string.
你根据正则表达式测试你的字符串，如果有一些匹配，你会得到第一个也是唯一的第一个，如果没有 $result 将是一个空字符串。
If you need to get more than the first result you can iterate over the $regs array. And of you need to find any other tag change the regular expresión to macht it, for example to find IMAGE tags you use:
如果您需要获得比第一个结果更多的结果，您可以遍历 $regs 数组。并且您需要找到任何其他标签，更改常规表达式以匹配它，例如找到您使用的 IMAGE 标签：
(<img[^>]*>.*?</img>)
EDIT:If you are processing line by line (with only the tag you are looking for) you can put ^...$ around the expresion to match a full line, like this:
编辑：如果您正在逐行处理（只有您正在寻找的标签），您可以在表达式周围放置 ^...$ 以匹配整行，如下所示：
if (preg_match('%^(<p[^>]*>.*?</p>)$%im', $subject, $regs)) {
$result = $regs[1];
} else {
$result = "";
}
HTH, Regards.
HTH，问候。
回答by Fantast
Prevent from include <pre> tag, can use:
防止包含 <pre> 标签，可以使用：
if (preg_match('/(<p(>|\s+[^>]*>).*?<\/p>)/i', $subject, $regs)) {
$result = $regs[1];
} else {
$result = "";
}
回答by benhowdle89
if (preg_match("/\b1\b/i", "some content, paragraph 1")) {
echo "A match was found.";
} else {
echo "A match was not found.";
}
Where 1 is the matched term...
其中 1 是匹配项...
Is this is any help?
这有什么帮助吗？
