php 获取 url 中最后一个 / 之后的字符
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Get characters after last / in url
提问by Johan
I want to get the characters after the last / in an url like http://www.vimeo.com/1234567
我想在 url 中的最后一个 / 之后获取字符 http://www.vimeo.com/1234567
How do I do with php?
我如何处理 php？
回答by DisgruntledGoat
Very simply:
很简单：
$id = substr($url, strrpos($url, '/') + 1);
strrposgets the position of the last occurrence of the slash; substrreturns everything after that position.
strrpos获取最后一次出现斜杠的位置；substr返回该位置之后的所有内容。
As mentioned by redanimalwar if there is no slash this doesn't work correctly since strrposreturns false. Here's a more robust version:
正如 redanimalwar 所提到的，如果没有斜线，这将无法正常工作，因为strrpos返回 false。这是一个更强大的版本：
$pos = strrpos($url, '/');
$id = $pos === false ? $url : substr($url, $pos + 1);
回答by GZipp
$str = basename($url);
回答by Sampson
You could explodebased on "/", and return the last entry:
您可以根据“/”爆炸，并返回最后一个条目：
print end( explode( "/", "http://www.vimeo.com/1234567" ) );
That's based on blowing the string apart, something that isn't necessary if you know the pattern of the string itself will not soon be changing. You could, alternatively, use a regular expression to locate that value at the end of the string:
这是基于将琴弦吹散，如果您知道琴弦本身的模式不会很快改变，则不需要这样做。或者，您可以使用正则表达式在字符串的末尾定位该值：
$url = "http://www.vimeo.com/1234567";
if ( preg_match( "/\d+$/", $url, $matches ) ) {
print $matches[0];
}
回答by Gabriel
回答by ghostdog74
$str = "http://www.vimeo.com/1234567";
$s = explode("/",$str);
print end($s);
回答by nikc.org
array_pop(explode("/", "http://vimeo.com/1234567"));will return the last element of the example url
array_pop(explode("/", "http://vimeo.com/1234567"));将返回示例 url 的最后一个元素
回答by billynoah
Two one liners - I suspect the first one is faster but second one is prettier and unlike end()and array_pop(), you can pass the result of a function directly to current()without generating any notice or warning since it doesn't move the pointer or alter the array.
两个一衬垫-我怀疑第一个是快，但第二个是漂亮，不像end()并且array_pop()，你可以直接传递函数的结果current()，而不会产生任何通知或警告，因为它不移动指针或改变的磁盘阵列。
$var = 'http://www.vimeo.com/1234567';
// VERSION 1 - one liner simmilar to DisgruntledGoat's answer above
echo substr($a,(strrpos($var,'/') !== false ? strrpos($var,'/') + 1 : 0));
// VERSION 2 - explode, reverse the array, get the first index.
echo current(array_reverse(explode('/',$var)));
回答by Mahmoud Zalt
Here's a beautiful dynamic function I wrote to remove last part of url or path.
这是我编写的一个漂亮的动态函数，用于删除 url 或路径的最后一部分。
/**
* remove the last directories
*
* @param $path the path
* @param $level number of directories to remove
*
* @return string
*/
private function removeLastDir($path, $level)
{
if(is_int($level) && $level > 0){
$path = preg_replace('#\/[^/]*$#', '', $path);
return $this->removeLastDir($path, (int) $level - 1);
}
return $path;
}
