如何在 JavaScript 中获取函数正文？
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How to get function body text in JavaScript?
提问by greepow
function derp() { a(); b(); c(); }
derp.toString()will return "function derp() { a(); b(); c(); }", but I only need the body of the function, so "a(); b(); c();", because I can then evaluate the expression. Is it possible to do this in a cross-browser way?
derp.toString()将返回"function derp() { a(); b(); c(); }"，但我只需要函数体，所以"a(); b(); c();"，因为我可以评估表达式。是否可以以跨浏览器的方式执行此操作？
回答by divide by zero
var entire = derp.toString();
var body = entire.slice(entire.indexOf("{") + 1, entire.lastIndexOf("}"));
console.log(body); // "a(); b(); c();"
Please use the search, this is duplicate of this question
请使用搜索，这是这个问题的重复
回答by Niet the Dark Absol
Since you want the text between the first {and last }:
由于您想要 first{和 last之间的文本}：
derp.toString().replace(/^[^{]*{\s*/,'').replace(/\s*}[^}]*$/,'');
Note that I broke the replacement down into to regexes instead of one regex covering the whole thing (.replace(/^[^{]*{\s*([\d\D]*)\s*}[^}]*$/,'$1')) because it's much less memory-intensive.
请注意，我将替换分解为正则表达式，而不是一个正则表达式覆盖整个内容 ( .replace(/^[^{]*{\s*([\d\D]*)\s*}[^}]*$/,'$1'))，因为它占用的内存要少得多。
回答by Ian
NOTE: The accepted answer depends on the interpreter not doing crazy things like throwing back comments between 'function' and '{'. IE8 will happily do this:
注意：接受的答案取决于解释器不会做一些疯狂的事情，比如在“函数”和“{”之间抛出注释。IE8 会很乐意这样做：
>>var x = function /* this is a counter-example { */ () {return "of the genre"};
>>x.toString();
"function /* this is a counter-example { */ () {return "of the genre"}"
回答by K3---rnc
A single-line, short regex example:
一个单行、简短的正则表达式示例：
var body = f.toString().match(/^[^{]+\{(.*?)\}$/)[1];
If you want to, eventually, evalthe script, and assuming the function takes no parameters, this should be a tiny bit faster:
如果你最终想要eval脚本，并假设函数不带参数，这应该快一点：
var body = '(' + f.toString() + ')()';
回答by micnic
You need something like this:
你需要这样的东西：
var content = derp.toString();
var body = content.match(/{[\w\W]*}/);
body = body.slice(1, body.length - 1);
console.log(body); // a(); b(); c();
