Python imaplib 获取正文电子邮件 gmail
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Python imaplib fetch body emails gmail
提问by kiriloff
I read this alreadyand wrote this script to fetch body for emails in some mail box which title begins with '$' and is sent by some sender.
我已经读过这篇文章并编写了这个脚本来获取某个邮箱中标题以“$”开头并由某个发件人发送的电子邮件正文。
import email, getpass, imaplib, os
detach_dir = "F:\PYTHONPROJECTS" # where you will save attachments
user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")
# connect to the gmail imap server
m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)
m.select("PETROLEUM") # here you a can choose a mail box like INBOX instead
# use m.list() to get all the mailboxes
resp, items = m.search(None, '(FROM "[email protected]")')
items = items[0].split() # getting the mails id
my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False
for emailid in items[::-1]:
resp, data = m.fetch(emailid, "(RFC822)")
if ( break_ ):
break
for response_part in data:
if isinstance(response_part, tuple):
msg = email.message_from_string(response_part[1])
varSubject = msg['subject']
if varSubject[0] == '$':
msg_cnt += 1
my_msg.append(msg)
print msg_cnt
print email.message_from_string(response_part[1])
if ( msg_cnt == 5 ):
break_ = True
if I print email.message_from_string(response_part[1]), I can see it contains first information (header, from, to, date...), the the full text body. But, I cannot fetch the body itself. email.message_from_string(response_part[0])prints mails IDS, and email.message_from_string(response_part[2])is out of range. email.message_from_string(response_part[1][0])neither is doing it.
如果我打印email.message_from_string(response_part[1])，我可以看到它包含第一个信息（标题，从，到，日期......），全文正文。但是，我无法取回尸体本身。email.message_from_string(response_part[0])打印邮件 IDS，并且email.message_from_string(response_part[2])超出范围。email.message_from_string(response_part[1][0])两者都没有这样做。
Thanks and regards.
感谢致敬。
UPDATE
更新
Now, I can almost have body text. However, it is still spoilt by an information statement coming first. I get as a result
现在，我几乎可以拥有正文了。然而，它仍然被首先出现的信息声明破坏了。结果我得到
From nobody Tue Dec 25 11:42:58 2012
US=3D.030
EastCst=3D.036
NewEng=3D.205
CenAtl=3D.149
LwrAtl=3D.921
Midwst=3D.984
GulfCst=3D.945
RkyMt=3D.195
WCst=3D.187
CA=3D.268
and I would like to get rid of From nobody Tue Dec 25 11:42:58 2012which is information. I know I could parse text look for first relevant line... i know.
我想摆脱From nobody Tue Dec 25 11:42:58 2012哪些是信息。我知道我可以解析文本查找第一个相关行......我知道。
The code for achieving so (to plug in my first sample) is
实现这一点的代码（插入我的第一个示例）是
if varSubject[0] == '$':
r, d = m.fetch(emailid, "(UID BODY[TEXT])")
msg_cnt += 1
my_msg.append(msg)
print email.message_from_string(d[0][1])
Do you have a better way (no info string) ??? More: what is the command to now fetch the date ? I know that I can do varDate = msg['date']where suited above, but how to just fetch day-month-year ? THANKS
你有更好的方法吗（没有信息字符串）？？？更多：现在获取日期的命令是什么？我知道我可以varDate = msg['date']在上面适合的地方做，但是如何只获取 day-month-year ？谢谢
采纳答案by damzam
You can get the contents of the body by doing any of the following
您可以通过执行以下任一操作来获取正文的内容
msg.as_string()
str(msg)
repr(msg)
http://docs.python.org/2.7/library/email.message.html#email.message.Message
http://docs.python.org/2.7/library/email.message.html#email.message.Message
回答by Edward Chapman
I've managed to get this to work using Gmail, it extracts the useful bits and outputs them to text files:
我设法使用 Gmail 使其工作，它提取有用的位并将它们输出到文本文件：
import datetime
import email
import imaplib
import mailbox
EMAIL_ACCOUNT = "[email protected]"
PASSWORD = "your password"
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login(EMAIL_ACCOUNT, PASSWORD)
mail.list()
mail.select('inbox')
result, data = mail.uid('search', None, "UNSEEN") # (ALL/UNSEEN)
i = len(data[0].split())
for x in range(i):
latest_email_uid = data[0].split()[x]
result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
# result, email_data = conn.store(num,'-FLAGS','\Seen')
# this might work to set flag to seen, if it doesn't already
raw_email = email_data[0][1]
raw_email_string = raw_email.decode('utf-8')
email_message = email.message_from_string(raw_email_string)
# Header Details
date_tuple = email.utils.parsedate_tz(email_message['Date'])
if date_tuple:
local_date = datetime.datetime.fromtimestamp(email.utils.mktime_tz(date_tuple))
local_message_date = "%s" %(str(local_date.strftime("%a, %d %b %Y %H:%M:%S")))
email_from = str(email.header.make_header(email.header.decode_header(email_message['From'])))
email_to = str(email.header.make_header(email.header.decode_header(email_message['To'])))
subject = str(email.header.make_header(email.header.decode_header(email_message['Subject'])))
# Body details
for part in email_message.walk():
if part.get_content_type() == "text/plain":
body = part.get_payload(decode=True)
file_name = "email_" + str(x) + ".txt"
output_file = open(file_name, 'w')
output_file.write("From: %s\nTo: %s\nDate: %s\nSubject: %s\n\nBody: \n\n%s" %(email_from, email_to,local_message_date, subject, body.decode('utf-8')))
output_file.close()
else:
continue
