java 使用属性获取元素
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Getting element using attribute
提问by RAAAAM
I am parsing Xml using Java, i want to parse element with the help of attribute value.
我正在使用 Java 解析 Xml，我想在属性值的帮助下解析元素。
For example <tag1 att="recent">Data</tag1>
例如 <tag1 att="recent">Data</tag1>
In this i want to parse tag1 data using att value. I am new to java and xml. pls guide me.
在此我想使用 att 值解析 tag1 数据。我是java和xml的新手。请指导我。
回答by Buhake Sindi
There are ways to do this. You can use either, xPath (example), DOM Document or SAX Parser (example) to retrieve attribute value and tag elements.
有办法做到这一点。您可以使用 xPath（示例）、DOM 文档或 SAX 解析器（示例）来检索属性值和标记元素。
Here's related questions:
以下是相关问题：
This is a workaround to what you requested. I would never suggest that type of "hack", instead, use SAX instead (see example link).
这是您要求的解决方法。我永远不会建议使用这种类型的“hack”，而是使用 SAX（参见示例链接）。
public static Element getElementByAttributeValue(Node rootElement, String attributeValue) {
if (rootElement != null && rootElement.hasChildNodes()) {
NodeList nodeList = rootElement.getChildNodes();
for (int i = 0; i < nodeList.getLength(); i++) {
Node subNode = nodeList.item(i);
if (subNode.hasAttributes()) {
NamedNodeMap nnm = subNode.getAttributes();
for (int j = 0; j < nnm.getLength(); j++) {
Node attrNode = nnm.item(j);
if (attrNode.getNodeType == Node.ATTRIBUTE_NODE) {
Attr attribute = (Attr) attrNode;
if (attributeValue.equals(attribute.getValue()) {
return (Element)subNode;
} else {
return getElementByAttributeValue(subNode, attributeValue);
}
}
}
}
}
}
return null;
}
PS:Code comment not provided. It's given as an exercise to the reader. :)
PS：未提供代码注释。它作为练习提供给读者。:)
回答by Ramesh PVK
This is java code to get the child node with given attribute name and value. Is this what you are looking for
这是用于获取具有给定属性名称和值的子节点的 Java 代码。这是你想要的
public static Element getNodeWithAttribute(Node root, String attrName, String attrValue)
{
NodeList nl = root.getChildNodes();
for (int i = 0; i < nl.getLength(); i++) {
Node n = nl.item(i);
if (n instanceof Element) {
Element el = (Element) n;
if (el.getAttribute(attrName).equals(attrValue)) {
return el;
}else{
el = getNodeWithAttribute(n, attrName, attrValue); //search recursively
if(el != null){
return el;
}
}
}
}
return null;
}
回答by ??? ?????' ???? ?????
It is a old question but you may use HTMLUnit
这是一个老问题，但您可以使用 HTMLUnit
HtmlAnchor a = (HtmlAnchor)ele;
url = a.getHrefAttribute();
