C# 将日期时间转换为 JSON 日期时间
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Convert DateTime To JSON DateTime
提问by manoj
I have a WebService which return DateTime Field.
我有一个返回 DateTime 字段的 WebService。
I get a result /Date(1379048144000)/but
我得到了一个结果/Date(1379048144000)/但是
i want just 1379048144000how can i achieve that.
我想我1379048144000怎么能做到这一点。
[WebMethod]
public DateTime GetServerDate()
{
return DateTime.Now;
}
by setting Header Content-Type: application/json; charset=utf-8; i got a result like /Date(1379048144000)/.
通过设置 Header Content-Type: application/json; 字符集=utf-8；我得到了类似的结果/Date(1379048144000)/。
采纳答案by Joe
You could change your WS to return a long with the value of the DateTime. The value to return is the number of milliseconds since the Unix Epoch (01/01/1970). This could be done with an extension method on DateTimesomething like:
您可以更改您的 WS 以返回带有 DateTime 值的 long。要返回的值是自 Unix 纪元 (01/01/1970) 以来的毫秒数。这可以通过扩展方法来完成，DateTime例如：
public static class DateTimeExtensions
{
...
private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1);
public static long ToUnixTime(this DateTime dateTime)
{
return (dateTime - UnixEpoch).Ticks / TimeSpan.TicksPerMillisecond;
}
...
}
And your web service method might look something like:
您的 Web 服务方法可能类似于：
public long GetMyDate(...)
{
DateTime dateTime = ...;
return dateTime.ToUnixTime();
}
回答by Zaheer Ahmed
try regex:
尝试正则表达式：
var jsonDate = @"/Date(1379048144000)/";
var regex = /-?\d+/;
var jsonDate = re.exec(jsonDate);
var dateOriginal = new Date(parseInt(m[0]));
回答by mrakodol
in client side you can use this function to show a right date to client(I use it on my projects):
在客户端，您可以使用此功能向客户端显示正确的日期（我在我的项目中使用它）：
function parseJsonDate(jsonDate) {
var offset = new Date().getTimezoneOffset() * 60000;
var parts = /\/Date\((-?\d+)([+-]\d{2})?(\d{2})?.*/.exec(jsonDate);
if (parts[2] == undefined) parts[2] = 0;
if (parts[3] == undefined) parts[3] = 0;
d = new Date(+parts[1] + offset + parts[2] * 3600000 + parts[3] * 60000);
date = d.getDate() + 1;
date = date < 10 ? "0" + date : date;
mon = d.getMonth() + 1;
mon = mon < 10 ? "0" + mon : mon;
year = d.getFullYear();
return (date + "." + mon + "." + year);
};
This function is return right date in format: dd.mm.yyyy, but you can change it if you need. I hope that I help you.
此函数以格式：dd.mm.yyyy 返回正确的日期，但您可以根据需要更改它。我希望我能帮助你。
回答by Matias
U can always solve your problem when sending a date in a JSON object to JS by converting the date as follows:
将 JSON 对象中的日期发送给 JS 时，您总是可以通过如下转换日期来解决您的问题：
var myJSDate = (new Date(parseInt(obj.MyDate.substr(6)))).toJSON();
Where obj.Date contains the date you wanna format.
其中 obj.Date 包含您要格式化的日期。
Then u'll get something like this: "2013-10-25T18:04:17.289Z"
然后你会得到这样的信息：“2013-10-25T18:04:17.289Z”
U can always check it in Chrome console by writing:
您可以随时在 Chrome 控制台中通过编写以下内容来检查它：
(new Date()).toJSON();
Hope this helps!
希望这可以帮助！
回答by Ben
回答by Karan Thakkar
Simply write like this to convert your date string in JSON format.
只需像这样编写即可将日期字符串转换为 JSON 格式。
date = "{" + date + "}";
回答by viorel
There are two solutions:
有两种解决方案：
- client side:
- 客户端：
function ToJavaScriptDate(value) {
var pattern = /Date\(([^)]+)\)/;
var results = pattern.exec(value);
var dt = new Date(parseFloat(results[1]));
return (dt.getMonth() + 1) + "/" + dt.getDate() + "/" + dt.getFullYear();
}It is possible to need alsou to convert into data object var date = new Date(xxx)
也可能需要转换成数据对象 var date = new Date(xxx)
Server side:
Newtonsoft.Json.JsonConvert.SerializeObject(your_object)
服务器端：
Newtonsoft.Json.JsonConvert.SerializeObject(your_object)
