从 Instagram 中获取所有带有 PHP 特定主题标签的照片
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/11182191/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Get all photos from Instagram which have a specific hashtag with PHP
提问by Zeid Selimovic
I need to get some pictures which have a specific hashtag using PHP ? Any help will be awesome, or hint ?
我需要使用 PHP 获取一些具有特定主题标签的图片吗？任何帮助都会很棒，或提示？
采纳答案by Anirudh Ramanathan
There is the instagram public API's tags section that can help you do this.
instagram 公共 API 的标签部分可以帮助您做到这一点。
回答by kexxcream
Here's another example I wrote a while ago:
这是我前段时间写的另一个例子：
<?php
// Get class for Instagram
// More examples here: https://github.com/cosenary/Instagram-PHP-API
require_once 'instagram.class.php';
// Initialize class with client_id
// Register at http://instagram.com/developer/ and replace client_id with your own
$instagram = new Instagram('CLIENT_ID_HERE');
// Set keyword for #hashtag
$tag = 'KEYWORD HERE';
// Get latest photos according to #hashtag keyword
$media = $instagram->getTagMedia($tag);
// Set number of photos to show
$limit = 5;
// Set height and width for photos
$size = '100';
// Show results
// Using for loop will cause error if there are less photos than the limit
foreach(array_slice($media->data, 0, $limit) as $data)
{
// Show photo
echo '<p><img src="'.$data->images->thumbnail->url.'" height="'.$size.'" width="'.$size.'" alt="SOME TEXT HERE"></p>';
}
?>
回答by Gursharan Singh
If you only need to display the images base on a tag, then there is not to include the wrapper class "instagram.class.php". As the Media & Tag Endpoints in Instagram API do not require authentication. You can use the following curl based function to retrieve results based on your tag.
如果您只需要基于标签显示图像，则不需要包含包装类“instagram.class.php”。因为 Instagram API 中的媒体和标签端点不需要身份验证。您可以使用以下基于 curl 的函数根据您的标签检索结果。
function callInstagram($url)
{
$ch = curl_init();
curl_setopt_array($ch, array(
CURLOPT_URL => $url,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_SSL_VERIFYPEER => false,
CURLOPT_SSL_VERIFYHOST => 2
));
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
$tag = 'YOUR_TAG_HERE';
$client_id = "YOUR_CLIENT_ID";
$url = 'https://api.instagram.com/v1/tags/'.$tag.'/media/recent?client_id='.$client_id;
$inst_stream = callInstagram($url);
$results = json_decode($inst_stream, true);
//Now parse through the $results array to display your results...
foreach($results['data'] as $item){
$image_link = $item['images']['low_resolution']['url'];
echo '<img src="'.$image_link.'" />';
}
回答by Szymon Je?
Since Nov 17, 2015 you have to authenticate users to make any (even such as "get some pictures who have specific hashtag") requests. See the Instagram Platform Changelog:
自 2015 年 11 月 17 日起，您必须对用户进行身份验证才能发出任何（甚至例如“获取具有特定主题标签的图片”）请求。查看Instagram 平台更新日志：
Apps created on or after Nov 17, 2015: All API endpoints require a valid access_token. Apps created before Nov 17, 2015: Unaffected by new API behavior until June 1, 2016.
2015 年 11 月 17 日或之后创建的应用：所有 API 端点都需要有效的 access_token。2015 年 11 月 17 日之前创建的应用程序：在 2016 年 6 月 1 日之前不受新 API 行为的影响。
this makes now all answers given here before June 1, 2016 no longer useful.
这使得现在在 2016 年 6 月 1 日之前给出的所有答案都不再有用。
回答by AHSAN KHAN
I have set a php code which can help in case you want to access Instagram images without api on basis of hashtag
我已经设置了一个 php 代码，如果您想根据主题标签访问没有 api 的 Instagram 图像，它可以提供帮助
回答by kexxcream
To get more than 20 you can use a load more button.
要获得超过 20 个，您可以使用加载更多按钮。
index.php
索引.php
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title>Instagram more button example</title>
<!--
Instagram PHP API class @ Github
https://github.com/cosenary/Instagram-PHP-API
-->
<style>
article, aside, figure, footer, header, hgroup,
menu, nav, section { display: block; }
ul {
width: 950px;
}
ul > li {
float: left;
list-style: none;
padding: 4px;
}
#more {
bottom: 8px;
margin-left: 80px;
position: fixed;
font-size: 13px;
font-weight: 700;
line-height: 20px;
}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script>
$(document).ready(function() {
$('#more').click(function() {
var tag = $(this).data('tag'),
maxid = $(this).data('maxid');
$.ajax({
type: 'GET',
url: 'ajax.php',
data: {
tag: tag,
max_id: maxid
},
dataType: 'json',
cache: false,
success: function(data) {
// Output data
$.each(data.images, function(i, src) {
$('ul#photos').append('<li><img src="' + src + '"></li>');
});
// Store new maxid
$('#more').data('maxid', data.next_id);
}
});
});
});
</script>
</head>
<body>
<?php
/**
* Instagram PHP API
*/
require_once 'instagram.class.php';
// Initialize class with client_id
// Register at http://instagram.com/developer/ and replace client_id with your own
$instagram = new Instagram('ENTER CLIENT ID HERE');
// Get latest photos according to geolocation for V?xj?
// $geo = $instagram->searchMedia(56.8770413, 14.8092744);
$tag = 'sweden';
// Get recently tagged media
$media = $instagram->getTagMedia($tag);
// Display first results in a <ul>
echo '<ul id="photos">';
foreach ($media->data as $data)
{
echo '<li><img src="'.$data->images->thumbnail->url.'"></li>';
}
echo '</ul>';
// Show 'load more' button
echo '<br><button id="more" data-maxid="'.$media->pagination->next_max_id.'" data-tag="'.$tag.'">Load more ...</button>';
?>
</body>
</html>
ajax.php
ajax.php
<?php
/**
* Instagram PHP API
*/
require_once 'instagram.class.php';
// Initialize class for public requests
$instagram = new Instagram('ENTER CLIENT ID HERE');
// Receive AJAX request and create call object
$tag = $_GET['tag'];
$maxID = $_GET['max_id'];
$clientID = $instagram->getApiKey();
$call = new stdClass;
$call->pagination->next_max_id = $maxID;
$call->pagination->next_url = "https://api.instagram.com/v1/tags/{$tag}/media/recent?client_id={$clientID}&max_tag_id={$maxID}";
// Receive new data
$media = $instagram->getTagMedia($tag,$auth=false,array('max_tag_id'=>$maxID));
// Collect everything for json output
$images = array();
foreach ($media->data as $data) {
$images[] = $data->images->thumbnail->url;
}
echo json_encode(array(
'next_id' => $media->pagination->next_max_id,
'images' => $images
));
?>
instagram.class.php
instagram.class.php
Find the function getTagMedia() and replace with:
找到函数 getTagMedia() 并替换为：
public function getTagMedia($name, $auth=false, $params=null) {
return $this->_makeCall('tags/' . $name . '/media/recent', $auth, $params);
}
