C++ 如何在Makefile中定义几个包含路径
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How to define several include path in Makefile
提问by groovehunter
New to C++; Basic understanding of includes, libraries and the compile process. Did a few simple makefiles yet.
C++ 新手；对包含、库和编译过程的基本理解。还做了一些简单的makefile。
My current project involves using an informix DB api and i need to include header files in more than one nonstandard dirs. How to write that ? Havent found anything on the net, probably because i did not use good search terms
我当前的项目涉及使用一个 informix DB api，我需要在多个非标准目录中包含头文件。那怎么写？网上没找到，可能是因为我没有使用好的搜索词
This is one way what i tried (not working). Just to show the makefile
这是我尝试过的一种方式（不起作用）。只是为了显示makefile
LIB=-L/usr/informix/lib/c++
INC=-I/usr/informix/incl/c++ /opt/informix/incl/public
default: main
main: test.cpp
gcc -Wall $(LIB) $(INC) -c test.cpp
#gcc -Wall $(LIB) $(INC) -I/opt/informix/incl/public -c test.cpp
clean:
rm -r test.o make.out
回答by Antoine Pelisse
You have to prepend every directory with -I:
您必须在每个目录前加上-I：
INC=-I/usr/informix/incl/c++ -I/opt/informix/incl/public
回答by wilhelmtell
You need to use -Iwith each directory. But you can still delimit the directories with whitespace if you use (GNU) make's foreach:
您需要-I与每个目录一起使用。但是，如果您使用 (GNU) make's ，您仍然可以用空格分隔目录foreach：
INC=$(DIR1) $(DIR2) ...
INC_PARAMS=$(foreach d, $(INC), -I$d)
