php 如何将foreach中的字符串组合成单个字符串PHP
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How to combine strings inside foreach into single string PHP
提问by Wakanina
I have code like this
我有这样的代码
$word = 'foo';
$char_buff = str_split($word);
foreach ($char_buff as $chars){
echo var_dump($chars);
}
The output was
输出是
string(1) "f"
string(1) "o"
string(1) "o"
For some reasons, I want to make the output become only 1 string like this:
由于某些原因，我想让输出变成这样的只有 1 个字符串：
string(3) "foo"
I tried with this
我试过这个
$char.=$chars;
echo var_dump($char);
But it shows error Undefined variable: char.
但它显示错误Undefined variable: char。
回答by Sampson
I'm going to assume that you have a good reason for splitting it up, only to put it back together again:
我将假设您有充分的理由将其拆分，然后再将其重新组合在一起：
$word = 'foo';
$result = "";
$char_buff = str_split($word);
foreach ($char_buff as $char){
$result .= $char;
}
echo var_dump($result);
Which outputs the following:
输出以下内容：
string(3) "foo"
回答by Rosme
I would just use implode, much like this:
$string = implode('', $char_buff);
我只会使用内爆，就像这样：
$string = implode('', $char_buff);
回答by SeanWM
str_split()converts a string to an array. There's no need to use this function if you want to keep the whole word.
str_split()将字符串转换为数组。如果您想保留整个单词，则无需使用此功能。
回答by vectorialpx
So, why do you split it just to make it a string again?
那么，为什么要拆分它只是为了使它再次成为一个字符串？
$word='foo'
$char_buff = str_split($word);
$final = array();
foreach ($char_buff as $chars){
$final[] = $chars;
}
var_dump( implode('', $final) );
回答by Bart Friederichs
Kind of strange to split a string, and then glue it together again, but here goes:
拆分一个字符串，然后再次将其粘合在一起有点奇怪，但是这里是：
$word='foo'
$char_buff = str_split($word);
// this is what is missing, you have to define a variable first
$newword = "";
foreach ($char_buff as $chars){
$newword .= $chars;
}
echo var_dump($newword);
回答by Bart Friederichs
Sounds like you are looking for implode() http://php.net/manual/en/function.implode.php
听起来你正在寻找 implode() http://php.net/manual/en/function.implode.php
As for the code you posted $chars .= $char; is probably what you were trying to do
至于你发布的代码 $chars .= $char; 可能是你想要做的
回答by Tahir Yasin
<?php
$word = 'foo';
$char_buff = str_split($word);
// here is the trick
$length = count($char_buff);
$char_buff[$length] = $word;
foreach ($char_buff as $chars)
{
echo var_dump($chars);
}
?>
回答by xreyc_developer22
Maybe some of you are looking for this answer. I think var_dump() is no longer necessary for this problem.
也许你们中的一些人正在寻找这个答案。我认为 var_dump() 不再需要解决这个问题。
<?php
if(isset($_POST['test'])){
$result = '';
for($x=1;$x<=4;$x++){
$ans = $_POST['ans'.$x];
$result .= $ans;
}
echo $result;
}
?>
Here is the HTML
这是 HTML
<form role="form" method="post" action="<?php echo $url;?>">
<input type="checkbox" name="ans1" value="A">A
<input type="checkbox" name="ans2" value="B">B
<input type="checkbox" name="ans3" value="C">C
<input type="checkbox" name="ans4" value="D">D
<input type="submit" name="test" value="Submit Answer">
</form>