C语言 如何用 C 编写 echo 程序？
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How do I write an echo program in C?
提问by unj2
the output should be something like this:
输出应该是这样的：
Enter Character : a
Echo : a
I wrote
我写
int c;
while (c != EOF)
{
printf("\n Enter input: ");
c = getchar();
putchar(c);
}
But I get two Enter Input after the echos.
但是在回声之后我得到了两个 Enter Input。
采纳答案by Starkey
Two characters are retrieved during input. You need to throw away the carriage return.
在输入期间检索两个字符。你需要扔掉回车符。
int c = 0;
int cr;
while (c != EOF)
{
printf("\n Enter input: ");
c = getchar();
cr = getchar(); /* Read and discard the carriage return */
putchar(c);
}
回答by The Archetypal Paul
Homework?
在家工作？
If so, I won't give a complete answer/ You've probably got buffered input - the user needs to enter return before anything is handed back to your program. You need to find out how to turn this off.
如果是这样，我不会给出完整的答案/您可能已经获得了缓冲输入 - 用户需要在将任何内容交还给您的程序之前输入 return 。您需要了解如何关闭此功能。
(this is dependent on the environment of your program - if you could give more details of platform and how you are running the program, we could give better answers)
（这取决于您的程序的环境 - 如果您能提供更多有关平台的详细信息以及您如何运行程序，我们可以提供更好的答案）
回答by user411313
take fgets eg:
采取 fgets 例如：
char c[2];
if( fgets( c, 2, stdin ) )
putchar( *c );
else
puts("EOF");
and you dont have any problems with getchar/scanf(%c)/'\n' and so on.
并且您对 getchar/scanf(%c)/'\n' 等没有任何问题。
回答by d mohan
#include <stdio.h>
#include <conio.h>
main(){
int number;
char delimiter;
printf("enter a line of positive integers\n");
scanf("%d%c", &number, &delimiter);
while(delimiter!='\n'){
printf("%d", number);
scanf("%d%c", &number, &delimiter);
}
printf("\n");
getch();
}
回答by BrunoLM
Why don't you use scanfinstead?
你为什么不scanf改用？
Example:
例子：
char str[50];
printf("\n Enter input: ");
scanf("%[^\n]+", str);
printf(" Echo : %s", str);
return 0;
Outputs
输出
?
Enter input: xx
Echo : xx
