java org.json.simple.JSONArray 不能转换为 org.json.simple.JSONObject
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org.json.simple.JSONArray cannot be cast to org.json.simple.JSONObject
提问by Bufank85
I'm trying to read a JSON file in which I have a series of integer data but when read tells me it can not convert from JSONObject to JSONArray
我正在尝试读取一个 JSON 文件，其中有一系列整数数据，但是当读取时告诉我它无法从 JSONObject 转换为 JSONArray
Part of the JSON file structure is:
JSON 文件结构的一部分是：
{
"data": [
[1, 1, 1, 1, 1, 1, 1, 1],
[1, 1, 0, 0, 0, 0, 1, 1],
[1, 1, 0, 0, 0, 0, 1, 1],
[0, 1, 1, 0, 0, 1, 1, 0],
[0, 1, 1, 1, 1, 1, 1, 0],
[0, 0, 1, 1, 1, 1, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0]
],
"time": 0.2
},
Code:
代码：
public static void main(String[] args) throws InterruptedException {
JSONParser parser = new JSONParser();
try {
Object obj = parser.parse(new FileReader("C:\Carriots\dos.json"));
JSONObject jsonObject = (JSONObject) obj;
// loop array
JSONArray tag = (JSONArray) jsonObject.get("data");
Iterator iterator = tag.iterator();
while (iterator.hasNext()) {
System.out.println(iterator.next());
}
回答by ban-geoengineering
Try...
尝试...
JSONArray tag = jsonObject.getJSONArray("data");
JSONArray tag = jsonObject.getJSONArray("data");
回答by Shaishav Jogani
Try to use below to get JSONArray from key data
尝试使用下面从键中获取 JSONArray data
JSONArray tag = (JSONArray) jsonObject.getJSONArray("data");
jsonObject.get()will return you Objectnot any JSONArray.
jsonObject.get()不会给你Object任何回报JSONArray。
回答by px06
import java.io.FileReader;
import org.json.simple.JSONObject;
import org.json.simple.JSONArray;
import org.json.simple.parser.JSONParser;
public class JSONTest {
public static void main(String[] args){
try {
JSONParser parser = new JSONParser();
Object obj = parser.parse(new FileReader("C:\Carriots\dos.json"));
JSONObject jsonObject = (JSONObject) obj;
JSONArray data = (JSONArray)jsonObject.get("data");
for(Object o: data){
System.out.println(o);
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
output:
输出：
[1,1,1,1,1,1,1,1]
[1,1,0,0,0,0,1,1]
[1,1,0,0,0,0,1,1]
[0,1,1,0,0,1,1,0]
[0,1,1,1,1,1,1,0]
[0,0,1,1,1,1,0,0]
[0,0,0,0,0,0,0,0]
[0,0,0,0,0,0,0,0]
回答by lars
You can use an iterator to process the array data. Be sure to use Object rather than String or Integer since you will get errors converting JSONObject to one of these values.
您可以使用迭代器来处理数组数据。请务必使用 Object 而不是 String 或 Integer，因为将 JSONObject 转换为这些值之一时会出错。
package jsonProcessing;
import java.io.FileReader;
import java.util.Iterator;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
public class JsonNumReader {
public static void main(String[] args) {
// TODO Auto-generated method stub
JSONParser parser = new JSONParser();
try {
JSONObject jsonObject = (JSONObject) parser.parse(new FileReader("C:/JSON/numbers.json"));
JSONArray array = (JSONArray)jsonObject.get("data");
Iterator<Object>iterator = array.iterator();
while(iterator.hasNext()){
System.out.println(iterator.next());
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
Output:
输出：
[1,1,1,1,1,1,1,1]
[1,1,0,0,0,0,1,1]
[1,1,0,0,0,0,1,1]
[0,1,1,0,0,1,1,0]
[0,1,1,1,1,1,1,0]
[0,0,1,1,1,1,0,0]
[0,0,0,0,0,0,0,0]
[0,0,0,0,0,0,0,0]
