JSON.parse：预期的属性名称或“}”
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JSON.parse: expected property name or '}'
提问by realnumber
Data contains (/"/):
数据包含（"//）：
{"test":"101","mr":"103","bishop":"102"}
script:
脚本：
console.log($.parseJSON(result));
I'm getting error,
我收到错误，
JSON.parse: expected property name or '}'.
回答by alchemication
Had same issue when used single quotes in JSON file, changed to double quotes for all string properties/values and it's working OK now, hope it helps anyone....
在 JSON 文件中使用单引号时遇到同样的问题，所有字符串属性/值更改为双引号，现在工作正常，希望它可以帮助任何人......
Change:
改变：
JSON.parse("{'wrongQuotes': 5}")
To:
到：
JSON.parse('{"rightQuotes": 5}')
回答by Jonathan M
If you're receiving the JSON with the encoded ", you'll have to replace each instance of "with a true "before doing JSON.parse. Something like:
如果您收到与编码的JSON "，你就必须更换的每个实例"有一个真正"做之前JSON.parse。就像是：
myJSONstring.replace(/"/ig,'"');
回答by kheengz
Change {"test":"101","mr":"103","bishop":"102"}
To '{"test":"101","mr":"103","bishop":"102"}'
更改{"test":"101","mr":"103","bishop":"102"}
为'{"test":"101","mr":"103","bishop":"102"}'
if this is coming from the server (PHP)
i.e <?php $php_var = ["test" => "101", "mr" => "103", "bishop" => "102"]?>
then on Javascriptend var javascript_var = $.parseJSON('<?= json_encode($php_var) ?>');
如果这是来自服务器（PHP），
即<?php $php_var = ["test" => "101", "mr" => "103", "bishop" => "102"]?>
在Javascript端var javascript_var = $.parseJSON('<?= json_encode($php_var) ?>')；
回答by Dazeh
For anyone who is using laravel blade and declaring a JS variable in a view.
对于使用 laravel 刀片并在视图中声明 JS 变量的任何人。
You need to use:
您需要使用：
var json = JSON.parse('{!! $json !!}');
Otherwise you will get this error due to the quotes being parsed as "
否则，由于引号被解析为“
