删除元素及其子元素的所有 JavaScript 事件侦听器？
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Remove all JavaScript event listeners of an element and its children?
提问by Tower
Is it possible to remove all event listeners of an element and its children? Something like:
是否可以删除元素及其子元素的所有事件侦听器？就像是：
myElem.removeEventListeners();
I need this because I have a complex element with events, and I need to create a copy of it -- like a static image that does not react to any events.
我需要这个，因为我有一个复杂的事件元素，我需要创建它的副本——就像一个对任何事件都没有反应的静态图像。
回答by gblazex
If you use cloneNode, the event listeners won't be copied.
如果使用cloneNode，则不会复制事件侦听器。
If you want a robust solution your best bet is probably to write a wrapper to attach/detachlisteners, and keep track of them yourself. Something like Dean Edwards' addEvent.
如果你想要一个强大的解决方案，你最好的办法可能是为attach/detach听众编写一个包装器，并自己跟踪他们。类似于Dean Edwards 的 addEvent。
回答by TNi
I do not know of one, and a search on Google didn't yield any obvious results. One easy, kludgy solution is to create a function that cycles through every event and sets it to null, such as
我不知道，在谷歌上搜索没有产生任何明显的结果。一个简单、笨拙的解决方案是创建一个函数来循环遍历每个事件并将其设置为null，例如
function removeEvents(obj)
{
obj.onblur = null;
obj.onchange = null;
obj.onclick = null;
// ...
}
Call this function as follows: removeEvents(myElem). A complete list of JavaScript event handlers can be found at http://www.elated.com/articles/events-and-event-handlers/.
调用该函数如下：removeEvents(myElem)。可以在http://www.elated.com/articles/events-and-event-handlers/找到 JavaScript 事件处理程序的完整列表。
Undoubtedly there is a more elegant way to write this function, but I don't know if there is a more elegant way to solve this problem. It would be lovely if someone knows of one. If you are binding events through a JavaScript library, such as jQuery, there may be other, better options.
无疑有更优雅的方式来写这个函数，但是不知道有没有更优雅的方式来解决这个问题。如果有人知道，那就太好了。如果您通过 JavaScript 库（例如 jQuery）绑定事件，那么可能还有其他更好的选择。
