Java 发送带有标头的 HTTP GET 请求
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Send HTTP GET request with header
提问by Jovan
From my Android app I want to request a URL with GET parameters and read the response.
In the request I must add a x-zipheader.
从我的 Android 应用程序中，我想请求一个带有 GET 参数的 URL 并读取响应。在请求中，我必须添加一个x-zip标头。
The URL is something like
网址是这样的
http://example.com/getmethod.aspx?id=111&method=Test
Can some one provide me code for that?
有人可以为我提供代码吗？
Two things are important: that it is a GET request and contains the x-zipheader .
有两件事很重要：它是一个 GET 请求并包含x-zipheader 。
EDIT:
编辑：
try {
HttpClient client = new DefaultHttpClient();
String getURL = "http://example.com/getmethod.aspx?id=111&method=Test";
HttpGet get = new HttpGet(getURL);
get.setHeader("Content-Type", "application/x-zip");
HttpResponse responseGet = client.execute(get);
HttpEntity resEntityGet = responseGet.getEntity();
if (resEntityGet != null) {
//do something with the response
Log.i("GET ",EntityUtils.toString(resEntityGet));
}
} catch (Exception e) {
e.printStackTrace();
}
I try with this code but I get code with .net error: Object reference not set to an instance of an object...I think but I'm not sure this if for x-zipheader, is header in my code ok?
我尝试使用此代码，但我得到的代码带有 .net 错误：Object reference not set to an instance of an object...我想，但我不确定这是否用于x-zip标头，我的代码中的标头是否正常？
采纳答案by mportuesisf
Here's a code excerpt we're using in our app to set request headers. You'll note we set the CONTENT_TYPE header only on a POST or PUT, but the general method of adding headers (via a request interceptor) is used for GET as well.
这是我们在应用程序中用于设置请求标头的代码摘录。您会注意到我们仅在 POST 或 PUT 上设置 CONTENT_TYPE 标头，但添加标头（通过请求拦截器）的一般方法也用于 GET。
/**
* HTTP request types
*/
public static final int POST_TYPE = 1;
public static final int GET_TYPE = 2;
public static final int PUT_TYPE = 3;
public static final int DELETE_TYPE = 4;
/**
* HTTP request header constants
*/
public static final String CONTENT_TYPE = "Content-Type";
public static final String ACCEPT_ENCODING = "Accept-Encoding";
public static final String CONTENT_ENCODING = "Content-Encoding";
public static final String ENCODING_GZIP = "gzip";
public static final String MIME_FORM_ENCODED = "application/x-www-form-urlencoded";
public static final String MIME_TEXT_PLAIN = "text/plain";
private InputStream performRequest(final String contentType, final String url, final String user, final String pass,
final Map<String, String> headers, final Map<String, String> params, final int requestType)
throws IOException {
DefaultHttpClient client = HTTPClientFactory.newClient();
client.getParams().setParameter(HttpProtocolParams.USER_AGENT, mUserAgent);
// add user and pass to client credentials if present
if ((user != null) && (pass != null)) {
client.getCredentialsProvider().setCredentials(AuthScope.ANY, new UsernamePasswordCredentials(user, pass));
}
// process headers using request interceptor
final Map<String, String> sendHeaders = new HashMap<String, String>();
if ((headers != null) && (headers.size() > 0)) {
sendHeaders.putAll(headers);
}
if (requestType == HTTPRequestHelper.POST_TYPE || requestType == HTTPRequestHelper.PUT_TYPE ) {
sendHeaders.put(HTTPRequestHelper.CONTENT_TYPE, contentType);
}
// request gzip encoding for response
sendHeaders.put(HTTPRequestHelper.ACCEPT_ENCODING, HTTPRequestHelper.ENCODING_GZIP);
if (sendHeaders.size() > 0) {
client.addRequestInterceptor(new HttpRequestInterceptor() {
public void process(final HttpRequest request, final HttpContext context) throws HttpException,
IOException {
for (String key : sendHeaders.keySet()) {
if (!request.containsHeader(key)) {
request.addHeader(key, sendHeaders.get(key));
}
}
}
});
}
//.... code omitted ....//
}
回答by vipw
You do it exactly as you showed with this line:
您完全按照此行所示进行操作：
get.setHeader("Content-Type", "application/x-zip");
So your header is fine and the problem is some other input to the web service. You'll want to debug that on the server side.
所以你的标题很好，问题是网络服务的其他一些输入。您需要在服务器端调试它。
