如何在java中查找字符串是否包含“仅”特殊字符
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How to find if a string contains "ONLY" Special characters in java
提问by shwetha
Suppose I define a String as:
假设我将一个字符串定义为：
String splChrs = "/-@#$%^&_-+=()" ;
String inputString = getInputString(); //gets a String from end the user
I want to check if String "inputString" contains ONLYspecial characters contained in String "splChrs" i.e. I want to set a boolean flag as trueif inputStringcontained only characters present in "splChrs"
我想检查字符串“ inputString”是否仅包含字符串“ splChrs”中包含的特殊字符，即如果inputString仅包含“ splChrs”中存在的字符，我想将布尔标志设置为true
eg: String inputString = "#######@"; //set boolean flag=true
And boolean flag is set as falseif it contained any letters that did not contain in "splChrs"
如果布尔标志包含“ splChrs”中不包含的任何字母，则布尔标志设置为假
eg: String inputString = "######abc"; //set boolean flag=false
采纳答案by anubhava
You can use:
您可以使用：
String splChrs = "-/@#$%^&_+=()" ;
boolean found = inputString.matches("[" + splChrs + "]+");
PS:I have rearranged your characters in splChrsvariable to make sure hyphen is at starting to avoid escaping. I also removed a redundant (and problematic) hyphen from middle of the string which would otherwise give different meaning to character class (denoted range).
PS：我已经在splChrs变量中重新排列了你的字符，以确保连字符开始避免转义。我还从字符串中间删除了一个多余的（和有问题的）连字符，否则它会给字符类（表示范围）赋予不同的含义。
Thanks to @AlanMoore for this note about character in character class:
感谢@AlanMoore 关于字符类中字符的注释：
^if it's listed first; ] if it's not listed first; [anywhere; and &if it's followed immediately by another &.
^如果它首先列出；] 如果它没有首先列出；[任何地方；而&如果它是由另一个紧跟&。
回答by Cyclopes
Try this,
尝试这个，
if(inputString.matches("[" + splChrs + "]+")){
// set bool to true
}else{
// set bool to false
}
回答by java_newbie
don't invent bicycle, 'cause all those tasks are common mostly to everyone. I suggest using Apache Commons lib where it's possible: http://commons.apache.org/proper/commons-lang/javadocs/api-2.6/org/apache/commons/lang/StringUtils.html#containsOnly%28java.lang.String,%20char[]%29
不要发明自行车，因为所有这些任务对每个人来说都是共同的。我建议在可能的情况下使用 Apache Commons lib：http: //commons.apache.org/proper/commons-lang/javadocs/api-2.6/org/apache/commons/lang/StringUtils.html#containsOnly%28java.lang。字符串,%20char[]%29
containsOnly
只包含
public static boolean containsOnly(String str, char[] valid)
public static boolean containsOnly(String str, char[] valid)
Checks if the String contains only certain characters.
A null String will return false. A null valid character array will return false. An empty String (length()=0) always returns true.
StringUtils.containsOnly(null, *) = false
StringUtils.containsOnly(*, null) = false
StringUtils.containsOnly("", *) = true
StringUtils.containsOnly("ab", '') = false
StringUtils.containsOnly("abab", 'abc') = true
StringUtils.containsOnly("ab1", 'abc') = false
StringUtils.containsOnly("abz", 'abc') = false
Parameters:
str - the String to check, may be null
valid - an array of valid chars, may be null
Returns:
true if it only contains valid chars and is non-null
