jQuery 中的克隆样式？
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Clone style in jQuery?
提问by Royi Namir
I have a <span>called spn1, which has some style from inline + CSS file.
我有一个<span>叫做spn1，它有一些来自内联 + CSS 文件的样式。
I have another <span>called spn2.
我还有一个<span>叫spn2.
How can I clone spn1's completestyle into spn2?
我如何可以克隆spn1的完整的风格融入spn2？
I want spn2to look exactly (in style) like spn1.
我想spn2看起来完全（风格）像spn1.
采纳答案by Oleg Grishko
Take a look at this thread:
https://stackoverflow.com/a/6416527/541827
The idea is to copy all the style's properties from one item to another
看看这个线程：https:
//stackoverflow.com/a/6416527/541827
这个想法是将所有样式的属性从一个项目复制到另一个项目
Or just use the jquery.copycss.jsplugin, the answer is based on.
Usage:
或者只是使用jquery.copycss.js插件，答案是基于。
用法：
$('#some-element').copyCSS('#another-element'); // copy all styles
$('#some-element').copyCSS('#another-element', ['top', 'left']); // copy just top and left
$('#some-element').copyCSS('#another-element', null, ['top', 'left']); // copy everything except top and left
回答by Rory McCrossan
Try this:
尝试这个：
$("#spn2").attr("style", $("#spn1").attr("style"))
.addClass($("#spn1").attr("class"));
回答by Ates Goral
jQuery doesn't have any direct facilities for doing this. You will have to use plain old JavaScript to find a cross-browser way to copy over the computed styleof one element to another. This answerhas an implementation for a potential solution.
jQuery 没有任何直接的工具可以做到这一点。您将不得不使用普通的旧 JavaScript 来找到一种跨浏览器的方式来将一个元素的计算样式复制到另一个元素。这个答案有一个潜在解决方案的实现。
回答by Andrei
Try using this:
尝试使用这个：
document.getElementById("spn2").style = document.getElementById("spn1").style;
回答by Adam Neuwirth
If you just want the CSS, you can do the following:
如果您只想要 CSS，您可以执行以下操作：
let cssText = document.defaultView.getComputedStyle( $("#elementID"), "").cssText;
Then you can apply that to any new element.
然后您可以将其应用于任何新元素。
回答by techfoobar
UPDATE
更新
Check this fiddle: http://jsfiddle.net/9BJ5y/
检查这个小提琴：http: //jsfiddle.net/9BJ5y/
Better idea would be clone spn1 and replace spn2 with it.
更好的主意是克隆 spn1 并用它替换 spn2。
i.e. something like:
即类似：
var x = $('#spn2').html();
$('#spn2').replaceWith($('#spn1').clone().html(x).attr('id', 'spn2'));
回答by Hyman-all-trades
<div style='background-color:red; display:hidden' id='template'>
<span>Something</span>
</div>
var replica=$('#template').clone();
replica
.removeAttr('id')
.css('display', 'block')
.find('span').text('Whatever');
replica.appendTo('#container');
回答by Reinstate Monica Cellio
Is there a reason you're not simply doing .clone(true)?
是否有理由不简单地执行 .clone(true)？
http://jsfiddle.net/johncmolyneux/6Fz84/
http://jsfiddle.net/johncmolyneux/6Fz84/
This example copies inline and class styles, but not id styles (which could be very useful).
此示例复制内联和类样式，但不复制 id 样式（这可能非常有用）。
回答by leopic
Why not applying whatever rules to both elements at the time?
为什么不在当时对这两个元素应用任何规则？
Something like:
就像是：
$('spn1','spn2').css({color: 'red'});
You could use multiple selectors http://api.jquery.com/multiple-selector/
您可以使用多个选择器http://api.jquery.com/multiple-selector/
