xcode 二元运算符“..<”不能应用于“Int”和“CGFloat”类型的操作数
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Binary operator '..<' cannot be applied to operands of type 'Int' and 'CGFloat'
提问by Sharukh
I'm trying to create a for loop but can't seem to understand how to get rid of this error
我正在尝试创建一个 for 循环，但似乎无法理解如何摆脱这个错误
My code:
我的代码：
for i:CGFloat in 0 ..< 2 + self.frame.size.width / (movingGroundTexture.size().width) {
let sprite = SKSpriteNode(texture: movingGroundTexture)
sprite.zPosition = 0
sprite.anchorPoint = CGPointMake(0, 0)
sprite.position = CGPointMake(i * sprite.size.width, 0)
addChild(sprite)
}
The error is on forline on self.frame.size.widthand (movingGroundTexture.aize().width)
错误for在线self.frame.size.width并且(movingGroundTexture.aize().width)
回答by Hamish
You cannot create a CountableRange(or CountableClosedRange) with floating point types.
您不能使用浮点类型创建CountableRange(或CountableClosedRange)。
You either want to convert your 2 + self.frame.size.width / movingGroundTexture.size().widthto an Int:
您要么想将您的转换2 + self.frame.size.width / movingGroundTexture.size().width为Int：
for i in 0 ..< Int(2 + self.frame.size.width / movingGroundTexture.size().width) {
// i is an Int
}
Or you want to use stride(Swift 2 syntax):
或者你想使用stride（Swift 2 语法）：
for i in CGFloat(0).stride(to: 2 + self.frame.size.width / movingGroundTexture.size().width, by: 1) {
// i is a CGFloat
}
Swift 3 syntax:
Swift 3 语法：
for i in stride(from: 0, to: 2 + self.frame.size.width / movingGroundTexture.size().width, by: 1) {
// i is a CGFloat
}
Depends on whether you need floating point precision or not. Note that if your upper bound is a non-integral value, the strideversion will iterate one more time than the range operator version, due to the fact that Int(...)will ignore the fractional component.
取决于您是否需要浮点精度。请注意，如果您的上限是非整数值，则该stride版本将比范围运算符版本多迭代一次，因为Int(...)会忽略小数部分。
回答by Code Different
You have to convert the right side of the range to an integer type, like Intor UInt:
您必须将范围的右侧转换为整数类型，例如Intor UInt：
for i in 0 ..< Int(2 + self.frame.size.width / (movingGroundTexture.size().width)) {
...
}
