C# 逗号、空格或分号分隔字符串上的 Regex.Split()

Regex.Split() on comma, space or semi-colon delimitted string

提问by bflemi3

I'm trying to split a string that can either be comma, space or semi-colon delimitted. It could also contain a space or spaces after each delimitter. For example

我正在尝试拆分一个字符串，该字符串可以是逗号、空格或分号分隔的。它还可以在每个分隔符之后包含一个或多个空格。例如

22222,11111,23232 
OR
22222, 11111, 23232 
OR
22222;     11111; 23232
OR
22222 11111 23232 

Any one of these would produce an array with three values ["22222","11111","23232"]

其中任何一个都会产生一个包含三个值的数组 ["22222","11111","23232"]

So far I have var values = Regex.Split("22222, 11111, 23232", @"[\\s,;]+")but this produces an array with the second and third values including the space(s) like so:

到目前为止，我有，var values = Regex.Split("22222, 11111, 23232", @"[\\s,;]+")但这会生成一个包含第二个和第三个值的数组，包括空格，如下所示：

["22222"," 11111"," 23232"]

采纳答案by Cédric Bignon

You have two possibilities:

你有两种可能：

• Regex.Split
• String.Split

• Regex.Split
• String.Split

In this case, you want to split your string by specific delimiters caracters. String.Splithas been created for this special purpose. This method will be faster than Regex.Split.

在这种情况下，您希望按特定的分隔符字符拆分字符串。String.Split已为此特殊目的而创建。这种方法会比Regex.Split.

char[] delimiters = new [] { ',', ';', ' ' };  // List of your delimiters
var splittedArray = myString.Split(delimiters, StringSplitOptions.RemoveEmptyEntries);

回答by DarkWalker

Regex.Split("22222, 11111, 23232", @"[ ,;]+")

this worked for me

这对我有用

Also check answer below, if all you really need is split a string based on few char delimiters - string.split is probably a better solution

还要检查下面的答案，如果您真正需要的是根据几个字符分隔符拆分字符串 - string.split 可能是更好的解决方案

回答by JDB still remembers Monica

You are using an @symbol for your string, so the "\"is being interpreted as a literal slash. So your character class is actually reading as a "\", an "s", a ","or a ";". Remove the extra slash and it should work as desired:

您正在@为字符串使用符号，因此将"\"其解释为文字斜杠。因此，您的字符类实际上是读取为 a "\"、 an "s"、 a","或 a ";"。删除多余的斜杠，它应该可以按需要工作：

var values = Regex.Split("22222, 11111, 23232", @"[\s,;]+")

回答by Ani

To interpret "I'm trying to split a string that can either be comma, space or semi-colon delimited. It could also contain a space or spaces after each delimiter" literally, try:

要从字面上解释“我正在尝试拆分可以是逗号、空格或分号分隔的字符串。它还可以在每个分隔符后包含一个或多个空格”，请尝试：

@"[,;]\s*|\s+"

This has the property that consecutive delimiters (except white space) will notbe treated as a single delimiter.

这具有连续分隔符（空格除外）不会被视为单个分隔符的属性。

But if you want all consecutive delimiters to be treated as one, you might as well do:

但是，如果您希望所有连续的分隔符都被视为一个，您不妨这样做：

@"[,;\s]+"

Of course, in that case, string.Splitis a simpler option, as others have indicated.

当然，在这种情况下string.Split，正如其他人所指出的那样，这是一个更简单的选择。

回答by GRUNGER

Try this Regex pattern:

试试这个正则表达式模式：

([^,;\"\}\{\s*.]\d+)

For sample text:

对于示例文本：

{"123","456","789"}
1011,1213,1415
16, 17, 181920
212223;        242526;27
28 29 3031 

See demo.

见演示。