简单问题：如何将日期 (08-17-2011) 拆分为月、日、年？PHP
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Simple Question: How to split date (08-17-2011) into month, day, year? PHP
提问by David Meyer
I have a variable called $orderdate and it is set to a date format like this mm-dd-yyyy.
我有一个名为 $orderdate 的变量，它被设置为类似 mm-dd-yyyy 的日期格式。
In PHP how would I split this variable into $month, $day, $year?
在 PHP 中，我如何将此变量拆分为 $month、$day、$year？
Thanks for your help.
谢谢你的帮助。
回答by binaryLV
If you're sure about the format of input value, then:
如果您确定input value的格式，则：
$orderdate = explode('-', $orderdate);
$month = $orderdate[0];
$day = $orderdate[1];
$year = $orderdate[2];
You could also use preg_match():
您还可以使用preg_match()：
if (preg_match('#^(\d{2})-(\d{2})-(\d{4})$#', $orderdate, $matches)) {
$month = $matches[1];
$day = $matches[2];
$year = $matches[3];
} else {
echo 'invalid format';
}
Additionally, you can use checkdate()to validate the date.
此外，您可以使用checkdate()来验证日期。
回答by Kokos
If you are not certainabout the input format you can also do the following:
如果您不确定输入格式，您还可以执行以下操作：
$time = strtotime($input);
$day = date('d',$time);
$month = date('m',$time);
$year = date('Y',$time);
回答by Bhanu Krishnan
list($month, $day, $year) =explode("-",$orderdate);
回答by omar j
A good approach is to use date_parse_from_format().
一个好方法是使用date_parse_from_format()。
For your example:
对于您的示例：
$dateStr = '03-27-2015';
$dateArray = date_parse_from_format('m-d-Y', $dateStr);
This gives $dateArrayas:
这给出$dateArray：
Array
(
[year] => 2015
[month] => 3
[day] => 27
[hour] =>
[minute] =>
[second] =>
...
)
回答by RiaD
Use explodeto split string
使用explode来分割字符串
list($m,$d,$y)=explode('-',$date);
