windows Python中的相对路径问题
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Problem with relative path in Python
提问by matt b
I know this is a simple, beginner-ish Python question, but I'm having trouble opening a file using a relative path. This behavior seems odd to me (coming from a non-Python background):
我知道这是一个简单的初学者级 Python 问题，但是我在使用相对路径打开文件时遇到了问题。这种行为对我来说似乎很奇怪（来自非 Python 背景）：
import os, sys
titles_path = os.path.normpath("../downloads/movie_titles.txt")
print "Current working directory is {0}".format(os.getcwd())
print "Titles path is {0}, exists? {1}".format(movie_titles_path, os.path.exists(movie_titles_path))
titlesFile = open(movie_titles_path, 'r')
print titlesFile
This results in:
这导致：
C:\Users\Matt\Downloads\blah>testscript.py
Current working directory is C:\Users\Matt\Downloads\blah
Titles path is ..\downloads\movie_titles.txt, exists? False
Traceback (most recent call last):
File "C:\Users\Matt\Downloads\blah\testscript.py", line 27, in <module>
titlesFile = open(titles_path, 'r')
IOError: [Errno 2] No such file or directory: '..\downloads\movie_titles.txt'
However, a dir command shows this file at the relative path exists:
但是，dir 命令显示该文件在相对路径中存在：
C:\Users\Matt\Downloads\blah>dir /b ..\downloads\movie_titles.txt
movie_titles.txt
What's going on with how Python interprets relative paths on Windows? What is the correct way to open a file with a relative path?
Python 如何解释 Windows 上的相对路径？打开具有相对路径的文件的正确方法是什么？
Also, if I wrap my path in os.path.abspath(), then I get this output:
另外，如果我将路径包裹在 中os.path.abspath()，则会得到以下输出：
Current working directory is C:\Users\Matt\Downloads\blah
Titles path is C:\Users\Matt\Downloads\downloads\movie_titles.txt, exists? False
Traceback (most recent call last):
File "C:\Users\Matt\Downloads\blah\testscript.py", line 27, in <module>
titlesFile = open(titles_path, 'r')
IOError: [Errno 2] No such file or directory: 'C:\Users\Matt\Downloads\downloads\movie_titles.txt'
In this case, seems like the open()command is automatically escaping the \characters.
在这种情况下，似乎open()命令会自动转义\字符。
**Embarrassing final update: Looks like I munged a character in the pathanme :) The correct way to do this on Windows seems to be to use os.path.normpath(), as I did originally.
**令人尴尬的最终更新：看起来我在 pathanme 中添加了一个字符 :) 在 Windows 上执行此操作的正确方法似乎是使用os.path.normpath()，就像我最初所做的那样。
回答by Paul Fisher
normpathonly returns a normalized version of that particular path. It does not actually do the work of resolvingthe path for you. You might want to do os.path.abspath(yourpath).
normpath只返回该特定路径的规范化版本。它实际上并没有为您完成解决路径的工作。你可能想要做os.path.abspath(yourpath)。
Also, I'm assuming you're on IronPython. Otherwise, the standard way of expressing that string format would be:
另外，我假设您使用的是 IronPython。否则，表达该字符串格式的标准方法是：
"Current working directory is %s" % os.getcwd()
"Titles path is %s, exists? %s" % (movie_titles_path, os.path.exists(movie_titles_path))
(Sorry, this is only an answer to the halfway posted question. I'm puzzled about the full solution.)
（抱歉，这只是对中途问题的回答。我对完整的解决方案感到困惑。）
