java 在java中生成序列号
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Generating sequence number in java
提问by vignesh
I want to generate a sequence number starting from 00000001,00000002....(i need all these zero as well)Please help me..Thanks in advance..
我想生成一个从 00000001,00000002 开始的序列号......（我也需要所有这些零）请帮助我..提前谢谢..
回答by Kai G
You can just generate the sequence numbers as integers and then format them like this:
您可以将序列号生成为整数，然后像这样格式化它们：
String.format("%08d", yournumber);
See this question: How can I pad an integers with zeros on the left?
看到这个问题： 我怎样才能在左边用零填充整数？
回答by paxdiablo
You can just maintain that variable as an integer and use String.formatto format it.
您可以将该变量保持为整数并用于对其String.format进行格式化。
String s = String.format ("%08d", 42); // gives you "00000042"
回答by WhiteFang34
You just need to use string formattingto pad numbers with zeros:
您只需要使用字符串格式用零填充数字：
for (int i = 1; i < 1000; i++) {
String sequence = String.format("%08d", i);
}
