json Jackson 反序列化......意外令牌（END_OBJECT），
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Hymanson deserialization ... Unexpected token (END_OBJECT),
提问by Ankur
I am trying to deserialize a JSON array into a Java Collection using Hymanson. This motivated by the answers to this question I asked last night Can I instantiate a superclass and have a particular subclass be instantiated based on the parameters supplied.
我正在尝试使用 Hymanson 将 JSON 数组反序列化为 Java 集合。这是由我昨晚问的这个问题的答案所激发的，我可以实例化一个超类并根据提供的参数实例化一个特定的子类。
The error I am gettings is (line breaks added for readability):
我得到的错误是（为了可读性添加了换行符）：
org.codehaus.Hymanson.map.JsonMappingException:
Unexpected token (END_OBJECT), expected FIELD_NAME: missing property 'type'
that is to contain type id (for class sempedia.model.query.QueryValue)
at [Source: java.io.StringReader@325aef; line: 1, column: 175]
(through reference chain: sempedia.model.query.QueryProperty["values"])
My situation is quite complicated. My array contains objects which themselves contain a value which is an array. This array in turn contains values which are also objects but are not necessarily the same (thus polymorphism).
我的情况相当复杂。我的数组包含对象，这些对象本身包含一个数组值。该数组又包含也是对象但不一定相同的值（因此是多态性）。
Here is a sample JSON string:
这是一个示例 JSON 字符串：
[
{
"id":"74562",
"uri":"http://dbpedia.org/ontology/family",
"name":"family",
"values":[
{
"id":"74563",
"uri":"http://dbpedia.org/resource/Orycteropodidae",
"name":"Orycteropodidae"
}
],
"selected":false
},
{
"id":"78564",
"uri":"http://dbpedia.org/ontology/someNumber",
"name":"someNumber",
"values":[
{
"lower":"45",
"upper":"975",
}
],
"selected":true
}
]
I would like to use this (below) code or something similar to get an object which is an instance of Collection<QueryProperty>which I have called queryProperties
我想使用这个（下面）代码或类似的东西来获取一个对象，它是Collection<QueryProperty>我调用的一个实例queryProperties
ObjectMapper mapper = new ObjectMapper();
Collection<QueryProperty> queryProperties =
queryProperties = mapper.readValue(query,
new TypeReference<Collection<QueryProperty>>(){});
My classes for deserialization (they have public getters/setters which I am not printing) are listed below:
下面列出了我的反序列化类（它们有我没有打印的公共 getter/setter）：
public class QueryProperty {
int id;
String uri;
String name;
Set<QueryValue> values;
String selected;
}
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "type")
@JsonSubTypes({
@Type(value = ResourceQueryValue.class),
@Type(value = NumericQueryValue.class)
})
public abstract class QueryValue {
String type;
}
ResourceQueryValue
ResourceQueryValue
public class ResourceQueryValue extends QueryValue{
int id;
String uri;
String name;
}
NumericQueryValuethe same JSON doesn't include an object of this type.
NumericQueryValue相同的 JSON 不包含这种类型的对象。
public class NumericQueryValue extends QueryValue{
double lower;
double upper;
}
Initial part of Stack trace:
堆栈跟踪的初始部分：
org.codehaus.Hymanson.map.JsonMappingException: Unexpected token (END_OBJECT), expected FIELD_NAME: missing property 'type' that is to contain type id (for class sempedia.model.query.QueryValue)
at [Source: java.io.StringReader@325aef; line: 1, column: 175] (through reference chain: sempedia.model.query.QueryProperty["values"])
at org.codehaus.Hymanson.map.JsonMappingException.from(JsonMappingException.java:163)
at org.codehaus.Hymanson.map.deser.StdDeserializationContext.wrongTokenException(StdDeserializationContext.java:240)
at org.codehaus.Hymanson.map.jsontype.impl.AsPropertyTypeDeserializer.deserializeTypedFromObject(AsPropertyTypeDeserializer.java:86)
at org.codehaus.Hymanson.map.deser.AbstractDeserializer.deserializeWithType(AbstractDeserializer.java:89)
回答by Ankur
As often happens, writing out a question helps you see the solution. So I need to do two things.
正如经常发生的那样，写出一个问题可以帮助您找到解决方案。所以我需要做两件事。
Firstly I need to add the type information into the JSON - which is not what I really wanted to do, but I guess you need to provide that information somewhere.
首先，我需要将类型信息添加到 JSON 中 - 这不是我真正想做的，但我想您需要在某处提供该信息。
And then I need to edit the annotation on QueryValue to be:
然后我需要将 QueryValue 上的注释编辑为：
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "type")
@JsonSubTypes({
@Type(value = ResourceQueryValue.class, name = "ResourceQueryValue"),
@Type(value = NumericQueryValue.class, name= "NumericQueryValue")
})
