简单地从数组中删除空值 - javascript
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/16164699/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Remove empty values from array simply - javascript
提问by UllerUller
I have looked at previous Q/A and I did not find much help there. Mainly as I did not understand what was coded.
我查看了以前的问答，但没有找到太多帮助。主要是因为我不明白什么是编码。
I am just looking to remove any empty values in my array.
我只是想删除数组中的任何空值。
My simple approach - that is not working!
我的简单方法 - 这是行不通的！
My code is -
我的代码是 -
var colors = [a, b, c, d, e, f];
var newArray = [];
for (var i = 0; i < colors.length; i++) {
if (colors[i] !== 'undefined' || colors[i] !== null || colors[i] !== "") {
newArray.push(colors[i]);
}
}
console.log(newArray.length); // == 6
console.log(newArray) //== yellow,blue,red,,,
I would have thought that my if statement would filter all elements with value and push on to my new array.
I really need newArray length to equal 3 and just hold vales, no empty string ""should be in the newArray.
我原以为我的 if 语句会过滤所有具有值的元素并推送到我的新数组。我真的需要 newArray 长度等于 3 并且只保存 vales，""newArray 中不应该有空字符串。
Thank you in advance.
先感谢您。
回答by Bojan Kovacevic
use && instead of ||:
使用 && 代替 || ：
var colors = ["yellow", "","red", "blue", "", ""];
var newArray = [];
for (var i = 0; i < colors.length; i++) {
if (colors[i] !== undefined && colors[i] !== null && colors[i] !== "") {
newArray.push(colors[i]);
}
}
console.log(newArray.length); // == 3
console.log(newArray) //== yellow,blue,red,,,
回答by shishirmk
use && instead of ||:
使用 && 代替 || ：
var colors = ["yellow", "","red", "blue", "", ""];
var newArray = [];
for (var i = 0; i < colors.length; i++) {
if (colors[i] !== undefined && colors[i] !== null && colors[i] !== "") {
newArray.push(colors[i]);
}
}
console.log(newArray.length); // == 3
console.log(newArray) //== yellow,blue,red,,,
For your use case you could also use
对于您的用例，您还可以使用
for (var i = 0; i < colors.length; i++) {
if (colors[i]) {
newArray.push(colors[i]);
}
}
This will filter out any falsy values. Falsy values include
这将过滤掉任何虚假值。假值包括
false
0
""
null
undefined
NaN
回答by shakib
You can simply use colors[i] to existence checking,
您可以简单地使用颜色 [i] 进行存在检查，
var colors = ["yellow", "","red", "blue", "", "", true, 1];
var newArray = [];
for (var i = 0; i < colors.length; i++) {
if (typeof colors[i] == 'string' && colors[i]) {
newArray.push(colors[i]);
}
}
console.log(newArray) //["yellow", "red", "blue"]
relevant resource javascript type conversion
相关资源javascript类型转换
hope this helps.
希望这可以帮助。
回答by 3y3
If 'false' value is important then:
如果 'false' 值很重要，那么：
var colors = [0,1,'a',,'',null,undefined,false,true];
colors = colors.filter(function(e){
return (e===undefined||e===null||e==='')?false:~e;
});
else:
别的：
var colors = [0,1,'a',,'',null,undefined,false,true];
colors = colors.filter(function(e){return e;});
回答by Khalizar
var colors = ["yellow", null, "blue", "red", undefined, 0, ""];
// es5:
var newArray = colors.filter(function(e){return !!e;});
// es6:
var newArray = colors.filter((e)=>!!e);
console.log(newArray.length); // ==> 3
console.log(newArray) // ==> ["yellow","blue","red"]
