Python 如何将“subprocess.call”的输出捕获到文件中？
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How to capture the output from "subprocess.call" to a file?
提问by Dag
In my code I have a line similar to this:
在我的代码中，我有一行类似于：
rval = subprocess.call(["mkdir",directoryName], shell=True)
and I can check rvalto see if it is 0or 1, but if it is 1, I would like to have the text from the command "A subdirectory or file ben already exists."in a file format, so I can compare it to another file if I want to make sure the text is the same.
我可以检查rval它是否是0或1，但如果是1，我希望命令"A subdirectory or file ben already exists."中的文本采用文件格式，因此如果我想确保文本相同，我可以将其与另一个文件进行比较.
Is it possible to have a line like this, but I know this does not work
有没有可能有这样的一条线，但我知道这行不通
rval = subprocess.call(["mkdir",directoryName], shell=True) >> filename
so no matter what happens with the command, the text is captured in filename, and rvalstill has the return code?
所以无论命令发生什么，文本都会被捕获filename，并且rval仍然有返回码？
采纳答案by Mark Ransom
import subprocess
f = open(r'c:\temp\temp.txt','w')
subprocess.call(['dir', r'c:\temp'], shell=True, stdout=f)
f.close()
回答by btubbs
The subprocess module has a built in 'check_output' function for doing this:
subprocess 模块有一个内置的“check_output”函数来执行此操作：
In [11]: result = subprocess.check_output(['pwd'])
In [12]: print result
/home/vagrant
回答by Jatin Kumar
import subprocess
try:
result = subprocess.check_output(['dir', r'c:\temp'], shell=True)
print result
except subprocess.CalledProcessError as e:
return_code = e.returncode
You anyway need to use try catch because it throws exception if return code is non zero :)
你无论如何都需要使用 try catch 因为如果返回代码非零它会抛出异常:)
