typescript TS2339：类型 {} 上不存在属性
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TS2339: Property does not exist on type {}
提问by Richard
Please help me fix this compilation error.
请帮我修复这个编译错误。
Below you can see the compiler complaining that the Actionsobject on line 20 (I removed a few lines for clarity before posting this) is {}:
在下面，您可以看到编译器抱怨第 20 行的Actions对象（为了清楚起见，我在发布之前删除了几行）是 {}：
But below you can see in actions.tsthat Actionsis an object of type Actions, and it has the requested property (which is a function):
但是，下面你可以看到在actions.ts该操作是类型的对象操作，并具有所要求的特性（这是一个功能）：
And in the base code you can see in the DefinitelyTyped Altdefinition that createActionsshould return an object of type Actions:
在基本代码中，您可以在绝对类型的Alt定义中看到createActions应返回类型为Actions的对象：
So why is Typescript complaining that Actions is not of type Actions?
那么为什么 Typescript 会抱怨 Actions 不是 Actions 类型呢？
回答by mk.
You're using a module called "app/actions/actions". That module is actually not a module (a map of properties), but whatever's the result of flux.createACtions(Actions):
您正在使用一个名为"app/actions/actions". 该模块实际上不是模块（属性映射），但无论结果如何flux.createACtions(Actions)：
export = flux.createActions(Actions); // in actions.ts
What does that return? Because you're not specifying the generic for <T>, and because the params of createActionsdon't correctly include a Tfrom which it could infer, it assumes that Tis just {}. This was discussed hereand ultimately declined. So, as mentioned, you need to specify the generic:
那返回什么？因为您没有指定 for 的泛型<T>，并且因为 的 paramscreateActions没有正确包含T它可以推断的 a，所以它假设它T只是{}. 这在这里被讨论过，最终被拒绝了。因此，如前所述，您需要指定泛型：
export = flux.createActions<Actions>(Actions);
But to avoid this, you could change your local (or remote) alt.d.tsto be something like:
但是为了避免这种情况，您可以将本地（或远程）alt.d.ts更改为：
class Alt {
createActions<T extends ActionsClass>(con: ActionsClassConstructor<T>, ...): T;
}
type ActionsClassConstructor<T extends ActionsClass> = new (alt:Alt) => T;
This adds the generic type info needed to correctly infer based on the constructor you supply.
这添加了根据您提供的构造函数正确推断所需的通用类型信息。
