bash pgrep -f 带多个参数
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pgrep -f with multiple arguments
提问by tommsen
i try to find a specific process containing the term "someWord" and two other terms represented by $1 and $2
我试图找到一个包含术语“someWord”和另外两个由 $1 和 $2 表示的术语的特定过程
7 regex="someWord.*.*"
8 echo "$regex"
9 [ `pgrep -f $regex` ] && return 1 || return 0
which returns
返回
./test.sh foo bar
someWord.*foo bar.*
./test.sh: line 9: [: too many arguments
What happens to my regular expression? Doing that pgrep directly in the shell works fine.
我的正则表达式会发生什么？直接在 shell 中执行该 pgrep 工作正常。
回答by Steven Penny
Good sir, perhaps this
好先生，也许这个
[[ `pgrep -f "$regex"` ]] && return 1 || return 0
or this
或这个
[ "`pgrep -f '$regex'`" ] && return 1 || return 0
回答by chepner
First, there's no reason to wrap your pgrepcommand in anything. Just use its exit status:
首先，没有理由将您的pgrep命令包装在任何东西中。只需使用其退出状态：
pgrep -f "$regex" && return 1 || return 0.
If pgrepsucceeds, you'll return 1; otherwise, you'll return 0. However, all you're doing is reversing the expected exit codes. What you probably want to do is simply let the pgrepbe the last statement of your function; then the exit code of pgrepwill be the exit code of your function.
如果pgrep成功，您将返回 1；否则，您将返回 0。但是，您所做的只是反转预期的退出代码。您可能想要做的只是让 thepgrep成为您函数的最后一个语句；那么退出代码pgrep将是您的函数的退出代码。
something () {
...
regex="someWord.*.*"
echo "$regex"
pgrep -f $regex
}
回答by Anew
If you really want to do something in case your command returns an error:
如果您真的想执行某些操作，以防您的命令返回错误：
cmd="pgrep -f $regex"
if ! $cmd; then
echo "cmd failed."
else
echo "ok."
fi
