Javascript 使用 es6 导入和调用函数
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import and call a function with es6
提问by Mohamed El Mahallawy
Previously:
之前：
var debug = require('debug')('http')
, http = require('http')
, name = 'My App';
With es6, how can I import and invoke right away like the first line?
使用es6，如何像第一行一样立即导入和调用？
import debug from 'debug'();
is a no no?
是不是不是？
回答by loganfsmyth
You'll need two lines:
你需要两行：
import debugModule from 'debug';
const debug = debugModule('http');
The import syntax is a declarative import syntax, it does not execute any functions.
导入语法是声明性导入语法，它不执行任何函数。
回答by jmar777
is a no no?
是不是不是？
Correct. Keep in mind that the importstatement is analogous to more than a simple require()statement -- it also creates a binding of the "loaded" module to a local variable.
正确的。请记住，该import语句不仅仅是一个简单的require()语句——它还创建了“加载”模块与局部变量的绑定。
That is,
那是，
import debug from 'debug'();
...is more close in behavior/semantics to
...在行为/语义上更接近于
var debug = require('debug');
...than it is to simply
...而不是简单地
require('debug');
Analogies to commonjs-style module loaders will obviously break down at some point, but at the end of the day it's a "no no" due to the plain and simple fact that import debug from 'debug'doesn't actually resolve to anything that you can invoke (or otherwise reference).
与 commonjs 风格的模块加载器的类比在某些时候显然会崩溃，但归根结底，这是一个“不，不”，因为简单明了的事实实际上import debug from 'debug'并没有解析为您可以调用的任何内容（或以其他方式）参考）。
回答by Vidul
import http from "debug"; // not sure if this is the desired effect
