Python SyntaxError：解析时出现意外的 EOF

SyntaxError: unexpected EOF while parsing

提问by Quar

I have no idea why this does not work please help

我不知道为什么这不起作用请帮忙

import random
x = 0
z = input('?')
int(z)

def main():
    while x < z:
        n1 = random.randrange(1,3)
        n2 = random.randrange(1,3)
        t1 = n1+n2
        print('{0}+{1}={2}'.format(n1,n2,t1)

When i run this it outputs this error

当我运行它时它输出这个错误

File "/Users/macbook/Documents/workspace/gamlir_filar/samlagning.py", line 12

                                                ^
SyntaxError: unexpected EOF while parsing

I am using eclipse and python 3.3 and i have no idea why this happens. It sometimes outputs errors like this.

我正在使用 eclipse 和 python 3.3，我不知道为什么会发生这种情况。它有时会输出这样的错误。

回答by Ashwini Chaudhary

You're missing a closing parenthesis )in print():

你缺少一个右括号)中print()：

print('{0}+{1}={2}'.format(n1,n2,t1))

and you're also not storing the returned value from int(), so zis still a string.

并且您也没有存储从 返回的值int()，所以z仍然是一个字符串。

z = input('?')
z = int(z)

or simply:

或者干脆：

z = int(input('?'))

回答by Kaydell

Maybe this is what you mean to do:

也许这就是你的意思：

import random

x = 0
z = input('Please Enter an integer: ')
z = int(z) # you need to capture the result of the expressioin: int(z) and assign it backk to z

def main():
    for i in range(x,z):
        n1 = random.randrange(1,3)
        n2 = random.randrange(1,3)
        t1 = n1+n2
        print('{0}+{1}={2}'.format(n1,n2,t1))

main()

1. do z = int(z)
2. Add the missing closing parenthesis on the last line of code in your listing.
3. And have a for-loop that will iterate from x to z-1

1. 做 z = int(z)
2. 在清单的最后一行代码中添加缺少的右括号。
3. 并有一个从 x 迭代到 z-1 的 for 循环

Here's a link on the range() function: http://docs.python.org/release/1.5.1p1/tut/range.html

这是 range() 函数的链接：http: //docs.python.org/release/1.5.1p1/tut/range.html