在 PHP 中的另一个类中调用一个类
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Call a class inside another class in PHP
提问by Supernovah
Hey there I'm wondering how this is done as when I try the following code inside a function of a class it produces some php error which I can't catch
嘿，我想知道这是如何完成的，因为当我在类的函数中尝试以下代码时，它会产生一些我无法捕获的 php 错误
public $tasks;
$this->tasks = new tasks($this);
$this->tasks->test();
I don't know why the initiation of the class requires $this as a parameter either :S
我不知道为什么课程的启动需要 $this 作为参数：S
thanks
谢谢
class admin
{
function validate()
{
if(!$_SESSION['level']==7){
barMsg('YOU\'RE NOT ADMIN', 0);
return FALSE;
}else{
**public $tasks;** // The line causing the problem
$this->tasks = new tasks(); // Get rid of $this->
$this->tasks->test(); // Get rid of $this->
$this->showPanel();
}
}
}
class tasks
{
function test()
{
echo 'test';
}
}
$admin = new admin();
$admin->validate();
回答by Lance Kidwell
You can't declare the public $tasks inside your class's method (function.) If you don't need to use the tasks object outside of that method, you can just do:
您不能在类的方法（函数）中声明公共 $tasks。如果您不需要在该方法之外使用 tasks 对象，您可以这样做：
$tasks = new Tasks($this);
$tasks->test();
You only need to use the "$this->" when your using a variable that you want to be available throughout the class.
当您使用希望在整个类中可用的变量时，您只需要使用“$this->”。
Your two options:
你的两个选择：
class Foo
{
public $tasks;
function doStuff()
{
$this->tasks = new Tasks();
$this->tasks->test();
}
function doSomethingElse()
{
// you'd have to check that the method above ran and instantiated this
// and that $this->tasks is a tasks object
$this->tasks->blah();
}
}
or
或者
class Foo
{
function doStuff()
{
$tasks = new tasks();
$tasks->test();
}
}
with your code:
使用您的代码：
class Admin
{
function validate()
{
// added this so it will execute
$_SESSION['level'] = 7;
if (! $_SESSION['level'] == 7) {
// barMsg('YOU\'RE NOT ADMIN', 0);
return FALSE;
} else {
$tasks = new Tasks();
$tasks->test();
$this->showPanel();
}
}
function showPanel()
{
// added this for test
}
}
class Tasks
{
function test()
{
echo 'test';
}
}
$admin = new Admin();
$admin->validate();
回答by davidtbernal
You're problem is with this line of code:
你的问题是这行代码：
public $tasks;
$this->tasks = new tasks();
$this->tasks->test();
$this->showPanel();
The publickeyword is used in the definition of the class, not in a method of the class. In php, you don't even need to declare the member variable in the class, you can just do $this->tasks=new tasks()and it gets added for you.
该public关键字在类的定义中使用，而不是在类的方法。在 php 中，你甚至不需要在类中声明成员变量，你可以这样做$this->tasks=new tasks()，它会为你添加。
