java 正则表达式匹配一个数字后跟空格
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regex to match a number followed by spaces
提问by artfullyContrived
I'm looking to use reg-ex to split the following string
我正在寻找使用 reg-ex 来拆分以下字符串
1 hi my name is John. 2 I live at house 32. 3 I see stars.
to
到
[hi my name is John, I live at house 32. , I see stars]
Note that am trying to split on digit followed by a space
请注意，我试图在数字后跟一个空格上拆分
回答by h2ooooooo
Split on /(^|\b\s+)\d+\s+/g.
拆分/(^|\b\s+)\d+\s+/g。
Explanation:
解释：
(^|\b\s+)A collection of either^or\b\s+)^Start of the stringOR\b\s+a word boundaryfollowed by a space/tab repeated 1 or more times
\d+A digit between 0 and 9 repeated 1 or more times(so it'd match 1, 12, 123, etc.)\s+A space/tab repeated 1 or more times
(^|\b\s+)^或\b\s+) 的集合^字符串的开头OR\b\s+一个字边界后跟一个空格/片重复1次或多次
\d+0 到 9 之间的数字重复 1 次或多次（因此它匹配 1、12、123 等）\s+空格/制表符重复 1 次或多次
Edit:
编辑：
(^|\.\s+)\d+\s+might work better for you.
(^|\.\s+)\d+\s+可能更适合你。
回答by Babar
Maybe this will do: [0-9]{1}[\ ]
也许这会做： [0-9]{1}[\ ]
回答by gitaarik
Split on:
拆分：
/\d+ /
Only the first match will be empty because it's the match just before the first number: 1, so you gotta ignore that one.
只有第一个匹配项是空的，因为它是第一个数字之前的匹配项: 1，所以你必须忽略那个。
