ruby 将十六进制字符串转换为十六进制整数
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Convert a hex string to a hex int
提问by FrereDePute
I have to convert a hexadecimal string to a hexadecimal integer, like this:
我必须将十六进制字符串转换为十六进制整数,如下所示:
color = "0xFF00FF" #can be any color else, defined by functions
colorto = 0xFF00FF #copy of color, but from string to integer without changes
I can have RGB format too.
我也可以有RGB格式。
I'm obliged to do this because this function goes after :
我有义务这样做,因为此功能在:
def i2s int, len
i = 1
out = "".force_encoding('binary')
max = 127**(len-1)
while i <= len
num = int/max
int -= num*max
out << (num + 1)
max /= 127
i += 1
end
out
end
I saw herethat hexadecimal integers exist. Can someone help me with this problem?
我在这里看到存在十六进制整数。有人可以帮我解决这个问题吗?
回答by David Unric
You'd need supply integer base argument to String#to_imethod:
您需要为String#to_i方法提供整数基参数:
irb> color = "0xFF00FF"
irb> color.to_i(16)
=> 16711935
irb> color.to_i(16).to_s(16)
=> "ff00ff"
irb> '%#X' % color.to_i(16)
=> "0XFF00FF"
回答by Cu3PO42
First off, an integer is never hexadecimal. Every integer has a hexadecimal representation, but that is a string.
首先,整数永远不是十六进制。每个整数都有一个十六进制表示,但那是一个字符串。
To convert a string containing a hexadecimal representation of an integer with the 0xprefix to an integer in Ruby, call the function Integeron it.
要将包含带有0x前缀的整数的十六进制表示的字符串转换为Ruby 中的整数,请调用其Integer上的函数。
Integer("0x0000FF") # => 255
回答by wxianfeng
2.1.0 :402 > "d83d".hex
=> 55357
2.1.0 :402 > "d83d".hex
=> 55357

