java.util.regex.PatternSyntaxException：不匹配的关闭 ')' ：在 string.split 操作期间
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java.util.regex.PatternSyntaxException: Unmatched closing ')' : during string.split operation
提问by Abhidemon
I am trying to perform a split similar the following:
我正在尝试执行类似于以下内容的拆分：
String str = "({Somestring 1 with a lot of braces and commas}),({Somestring 12with a lot of braces and commas})";
println str.split("}),({");
But i see:
但我看到：
java.util.regex.PatternSyntaxException: Unmatched closing ')' near index 0 }),({
java.util.regex.PatternSyntaxException: 索引 0 附近不匹配的关闭 ')' }),({
Clearly , my string is being treated as a regular expression.
显然，我的字符串被视为正则表达式。
Is there a way i can escape this string?
有没有办法可以转义这个字符串？
回答by Jens
the character (and )and {and }are special character in regexp. you have to escape these:
字符(和)和{和}是正则表达式中的特殊字符。你必须逃避这些：
println str.split("\}\),\(\{");
回答by assylias
Instead of escaping the string manually you can also treat it like a literal as opposed to a regex with:
除了手动转义字符串，您还可以将其视为文字而不是正则表达式：
println str.split(Pattern.quote("}),({"));
回答by Ankur Singhal
Java charactersthat have to be escapedin regular expressionsare:
Java characters必须escaped在regular expressions：
.[]{}()*+-?^$|
.[]{}()*+-?^$|
public static void main(String[] args) {
String str = "({Somestring 1 with a lot of braces and commas}),({Somestring 12with a lot of braces and commas})";
String[] array = str.split("\}\),\(\{");
System.out.println(array.length);
}
