xcode 使用 UITapGestureRecognizer 传递参数
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Pass Parameter with UITapGestureRecognizer
提问by Joe Cade
Is there any way i can pass parameters with UITapGestureRecognizer? I've seen this answered for objective-c but couldn't find an answer for swift
有什么办法可以用 UITapGestureRecognizer 传递参数吗？我已经看到这个回答了objective-c，但找不到swift的答案
test.userInteractionEnabled = true
let tapRecognizer = UITapGestureRecognizer(target: self, action: Selector("imageTapped4:"))
// Something like text.myParamater
test.addGestureRecognizer(tapRecognizer)
And then receive myParameter under func imageTapped4(){}
然后在func imageTapped4(){}下接收myParameter
回答by JingJingTao
One approach would be to subclass UITapGestureRecognizer and then set a property, I've posted an example below. You could also do some check on the sender and check if equal to some tag, class, string, e.t.c
一种方法是将 UITapGestureRecognizer 子类化，然后设置一个属性，我在下面发布了一个示例。您还可以对发件人进行一些检查，并检查是否等于某个标签、类、字符串等
class ViewController: UIViewController {
@IBOutlet weak var label1: UILabel!
@IBOutlet weak var image: UIImageView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
image.userInteractionEnabled = true;
let tappy = MyTapGesture(target: self, action: #selector(self.tapped(_:)))
image.addGestureRecognizer(tappy)
tappy.title = "val"
}
func tapped(sender : MyTapGesture) {
print(sender.title)
label1.text = sender.title
}
}
class MyTapGesture: UITapGestureRecognizer {
var title = String()
}
There are lots of examples on SO, have a look, good luck.
SO上有很多例子，看看吧，祝你好运。
回答by Sachin Rasane
For Swift 4
对于 Swift 4
In Viewdidload
在视图加载中
let label = UILabel(frame: CGRect(x: 0, y: h, width: Int(self.phoneNumberView.bounds.width), height: 30))
label.textColor = primaryColor
label.numberOfLines = 0
label.font = title3Font
label.lineBreakMode = .byWordWrapping
label.attributedText = fullString
let phoneCall = MyTapGesture(target: self, action: #selector(self.openCall))
phoneCall.phoneNumber = "\(res)"
label.isUserInteractionEnabled = true
label.addGestureRecognizer(phoneCall)
Function as
作为
@objc func openCall(sender : MyTapGesture) {
let number = sender.phoneNumber
print(number)
}
Write Class as
将类写为
class MyTapGesture: UITapGestureRecognizer {
var phoneNumber = String()
}
Follow Step Properly and make change according to your variable , button ,label . It WORKS PROPERLY
正确执行步骤并根据您的变量、按钮、标签进行更改。它工作正常
回答by Mirko Brunner
The best way is to determind the parameter when the func imageTapped64is fired. You can get you params via the view (take a look to @Developer Sheldon answer)
or in many other ways.
最好的方法是在 funcimageTapped64被触发时确定参数。您可以通过视图（查看@Developer Sheldon 的回答）或许多其他方式获取参数。
