jQuery 来自选择框的jquery ajax调用

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/4555116/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-26 17:28:21  来源:igfitidea点击:

jquery ajax call from select box

jquery

提问by user545520

How to make ajax call from onchange event of select box using jquery? If anyone has a sample, please post the code.

如何使用jquery从选择框的onchange事件进行ajax调用?如果有人有示例,请发布代码。

回答by lk.annamalai

the below code is based on spring mvc architecture,

以下代码基于 spring mvc 架构,

$('#selectbox1').change(function() {
    var data = "";
    $.ajax({
        type:"GET",
        url : "controller mapping",
        data : "selectbox1_selectedvalue="+$(this).val(),
        async: false,
        success : function(response) {
            data = response;
            return response;
        },
        error: function() {
            alert('Error occured');
        }
    });
    var string = data.message.split(",");
    var array = string.filter(function(e){return e;});
    var select = $('selectbox2');
    select.empty();
    $.each(array, function(index, value) {          
        select.append(
                $('<option></option>').val(value).html(value)
            );
    });
        $('#selectbox2').show();
});

inside the html, i use like below to display the selectbox2 values,

在 html 中,我使用如下所示来显示 selectbox2 值,

<tr>
    <select id="selectbox1">
        <option value="value1">value1</option><option value="value2">value2</option>
    </select>
    <select id="selectbox2"></select>
</tr>

in the selectbox2, values are loaded from a controller using ajax call, in controller i return like below,

在selectbox2中,使用ajax调用从控制器加载值,在控制器中我返回如下,

    List<String> listvalues = listService.retrieveAll(searchTerm); // searchTerm is a selected value from selectbox1
String dummy = "";
for(int i=0; i<listvalues.size(); i++)
{
    dummy += listvalues.get(i)+",";
}
MessageValue messageValue = new MessageValue(dummy);
return messageValue;

回答by Mark Baijens

$("#selectboxid").change(function() {
  $.ajax({ url: "test.html", context: document.body, success: function(){
    $(this).addClass("done");
  }});
});